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nata0808 [166]
3 years ago
5

Acetic acid, ethanol, acetaldehyde and ethane form a series of 2-carbon molecules which differ in their extent of oxidation. Con

vert ethanol to the next more reduced form in that ordered series. HelpMarvin JS
Chemistry
1 answer:
yanalaym [24]3 years ago
7 0
<h2>CH_3CH_2OH  →  CH_3CHO </h2>

Explanation:

Ethanol can be oxidized to ethanal or acetaldehyde which is further oxidized to acid that is acetic acid.

CH_3CH_2OH→  CH_3CHO [oxidation by loss of hydrogen]

  • An oxidizing agent potassium dichromate(VI) solution is used to remove the hydrogen from the ethanol.  
  • An oxidizing agent used along with dilute sulphuric acid for acidification.

Acetaldehyde can also be reduced back to ethanol again by adding hydrogen to it by using a reducing agent that is sodium tetrahydro borate, NaBH4.

  • The oxidation of aldehydes to carboxylic acids can be done by the two-step process.  
  • In the first step, one molecule of water is added in the presence of a catalyst that is acidic.
  • There is a generation of a hydrate. (geminal 1,1-diol).

     CH_3CHO  →  CH_3CH_2COOH [reduction by the gain of electrons]

Here, the oxidizing agent used isCr_3O in the presence of acetone.

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if a baloon filled with dry hydrogen weighs 35 gram,but weighs 440 grams when filled with the vapour of an organic compound. cal
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1) The vapor density of the organic compound is approximately 12.57

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Explanation:

1) The mass of the balloon filled with dry hydrogen = 35 grams

The mass of the balloon filled with vapor of an organic compound = 440 grams

The vapor density = (Weight of a given volume of gas)/(Weight of equal volume of hydrogen)

The vapor density of the organic compound = (440)/(35) ≈ 12.57

The vapor density of the organic compound ≈ 12.57

2) The relative molar mass (RMM) = 2 × vapor density

The relative molar mass (RMM) of the organic compound = 2 × vapor density of the organic compound

The relative molar mass (RMM) of the organic compound ≈ 2 × 12.57 ≈ 25.14 grams  

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