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Dvinal [7]
3 years ago
14

true or false: ionic bonding involves the shareing of electrons, oxide ions have a 2+ charge , electrons have a negative charge

, a hydrogen molecule is held together by a strong covalent bond between two hydrogen atoms, a covalent bond is a shared pair of electrons.

Chemistry
2 answers:
Elis [28]3 years ago
7 0
Ionic bonding does not involve the sharing of electrons, that one is false. In ionic bonding, the metal's electrons are given to the non-metal, so that they're both like the nearest noble gas (full electron shells.) They are then drawn together because one has a negative charge (the non-metal) and one has a positive charge (the metal.)

Oxide ions have a 2+ charge: This is false, oxide ions have a 2- charge.

Electrons do have a negative charge, this is true.

Hydrogen molecule: pretty sure this is true. We know this because both atoms are non-metals.

The last one is true: a covalent bond is a shared pair of electrons between two atoms, however be aware that there can be more than one covalent bond between two molecules.


ozzi3 years ago
5 0

Answer:

  1. False , shared electrons cause covalent bonds
  2. False , they have 2- charge
  3. True
  4. True
  5. Truw
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How many grams of O2 are needed to react with 18.2 g of NH3?
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Answer:

44 g oxygen are needed.

Explanation:

Given data:

Mass of oxygen needed = ?

Mass of ammonia = 18.2 g

Solution:

Chemical equation:

4NH₃ + 5O₂   →  4NO + 6H₂O

Now we will calculate the number of moles of ammonia:

Number of moles = mass/molar mass

Number of moles = 18.2 g/ 17 g/mol

Number of moles = 1.1 mol

Now we will compare the moles of ammonia with oxygen from balance chemical equation.

                        NH₃              :                O₂

                          4                 :                 5

                          1.1                :              5/4×1.1 = 1.375 mol

Mass of oxygen needed:

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EXTRA POINTSSS 1. A solution at 25 degrees Celsius is 1.0 × 10–5 M H3O+. What is the concentration of OH– in this solution?
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Answer:

Concentration of OH⁻:

1.0 × 10⁻⁹ M.

Explanation:

The following equilibrium goes on in aqueous solutions:

\text{H}_2\text{O}\;(l)\rightleftharpoons \text{H}^{+}\;(aq) + \text{OH}^{-}\;(aq).

The equilibrium constant for this reaction is called the self-ionization constant of water:

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Note that water isn't part of this constant.

The value of K_w at 25 °C is 10^{-14}. How to memorize this value?

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  • However, [\text{OH}^{-}] = [\text{H}^{+}]=10^{-7}\;\text{mol}\cdot\text{dm}^{-3} for pure water.
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Back to this question. [\text{H}^{+}] is given. 25 °C implies that K_w = 10^{-14}. As a result,

\displaystyle [\text{OH}^{-}] = \frac{K_w}{[\text{H}^{+}]} = \frac{10^{-14}}{1.0\times 10^{-5}} = 10^{-9} \;\text{mol}\cdot\text{dm}^{-3}.

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