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3 years ago

Describe the movement of particles in a solid substance as it is heated to its boiling point.

Chemistry

1 answer:

olga nikolaevna [1]3 years ago

7 0

Answer:

in a solid particles or still but as it gets hot the particles will move around rapidly

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Compare the atomic sizes of sodium and magnesium. Explain.

mihalych1998 [28]

Answer:

Sodium atom is larger than Magnesium atom.

Explanation:

Looking at the electronic configurations of Sodium and Magnesium:

$_{11}Na: 1s^2 2s^2 p^6 3s^1\\\\_{12}Mg : 1s^2 2s^2 p^6 3s^2$ ,

we can see that they both have their valence electrons in the 3rd shell.

But because Magnesium has a higher nuclear charge of +12 because of its 12 protons than that of Sodium's +11, the nucleus of Magnesium attracts its outer electrons more strongly than Sodium does. This makes the Magnesium atom smaller.

5 0

2 years ago

20.0 g of Nitrogen is produced when oxygen gas reacts with NO gas. 29.8 L of oxygen is required at STP to produce this 20.0 g of

fiasKO [112]

The statement is false as 85675 grams of nitrogen dioxide is produced instead of 20 grams.

Explanation:

Balance equation for the reaction:

2NO + $O_{2}$ ⇒ 2N $O_{2}$

Data given:

mass of nitrogen produced = 20 gram

mass of oxygen = 29.8 litres or 29800 grams

0xygen is the limiting reagent so,

number of moles of oxygen: (atomic mass of 1 mole 32 grams/mole

number of moles = $\frac{mass}{atomic mass of 1 mole}$

putting the values in the equation:

= $\frac{29800}{32}$

= 931.5 moles

1 mole of oxygen reacts to give 2 moles of NO2

931.5 moles of oxygen will give x moles

$\frac{2}{1}$ = $\frac{x}{931.5}$

1862.5 moles of NO2 produced

in grams

mass = number of moles x atomic mass

mass = 1862.5 x 46.00

= 85675 grams

The statement is false as 85675 grams of nitrogen dioxide is produced instead of 20 grams as said in question.

7 0

3 years ago

3. Using the solubility of ionic compounds table and/or the solubility rules,

Klio2033 [76]

Answer:

Sugar, sodium chloride, and hydrophilic proteins

6 0

3 years ago

"how many grams of calcium are consumed when 156.8 ml of oxygen"

Akimi4 [234]

Your question is incomplete. However, I found a similar problem fromanother website as shown in the attached picture.

To solve this problem, you must know that at STP, the volume for any gas is 22.4 L/mol. So,

Moles O₂: 156.8 mL * 1 L/1000 mL* 1 mol/22.4 L = 0.007 moles
Mass calcium: 0.007 mol O₂ * 2 mol Ca/1 mol O₂ * 40 g/mol Ca = 0.56 g Ca

3 0

3 years ago

Determine the molar concentration of na+ and po4 3- in a 2.25 M Na3 PO4 solution

muminat

Answer:

A. The concentration of Na^+ in the solution is 6.75 M.

B. The concentration of PO4^3- in the solution is 2.25 M.

Explanation:

We'll begin by writing the balanced dissociation equation for Na3PO4.

This is illustrated below:

Na3PO4 will dissociate in solution as follow:

Na3PO4(aq) —> 3Na^+(aq) + PO4^3-(aq)

Thus, from the balanced equation above,

1 mole of Na3PO4 produce 3 moles of Na^+ and 1 mole of PO4^3-

A. Determination of the concentration of Na+ in 2.25 M Na3PO4 solution.

This can be obtained as follow:

From the balanced equation above,

1 mole of Na3PO4 produce 3 moles of Na^+.

Therefore, 2.25 M Na3PO4 solution will produce = (2.25 x 3) /1 = 6.75 M Na^+.

Therefore, the concentration of Na^+ in the solution is 6.75 M

B. Determination of the concentration of PO4^3- in 2.25 M Na3PO4 solution.

This can be obtained as follow:

From the balanced equation above,

1 mole of Na3PO4 produce 1 mole of PO4^3-

Therefore, 2.25 M Na3PO4 solution will also produce 2.25 M PO4^3-.

Therefore, the concentration of PO4^3- in the solution is 2.25 M.

7 0

3 years ago