2,240 divided by 28= 80. 80 times 32= 2,560. 2,560+2,240=4800. Figure out the rest alone xD
Answer:
6
Step-by-step explanation:
You must find the least common multiple of their schedules.
The numbers 3 and 2 are their own prime factors, so the least common multiple of 3 and 2 is 6.
Six weekends must pass until they can both have someone over on the same night.
The number line below shows that the first time their sleepovers coincide is Week 6.
Step-by-step explanation:
I hope u got ur answer ;)
if u have any more doubt ask me
Answer:
C. 150
Step-by-step explanation:
It's right on Plato.
I think it’s AC, but I may be wrong