P = 2(L + W)
P = 180
W = L - 24
now we sub
180 = 2(L + L - 24)
180 = 2(2L - 24)
180 = 4L - 48
180 + 48 = 4L
228 = 4L
228/4 = L
57 = L
W = L - 24
W = 57 - 24
W = 33
so ur length (L) = 57 ft and ur width (W) = 33 ft
This is only one equation. It is therefore not a system and you can not solve for two different variables y and z unless you have another equation to solve with. It.
(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
Answer:
32 = 26
d
2
= 32
Step-by-step explanation: UMU
Answer:
x = 24
Step-by-step explanation:
ABCD is a parallelogram.
Angle B and Angle C are adjacent (successive) angles.
Adjacent angles of a parallelogram are supplementary.
Therefore,
