Answer:
Well, how many were left over? Mrs. Adams has a muffin factory and made 1 million muffins. Carl ate 2/5 or 40% or 400,000 muffins, and John ate 25. 599,975 muffins were shipped for sale. That meets the stated requirements.
Hence, we have to guess there were supposed to be no muffins left over.
In that case, Mrs. Adams baked 125/3 muffins, Carl ate 2/5 of them = 50/3, leaving 75/3 = 25 for John.
Step-by-step explanation:
x muffins baked, 2/5 eaten by Carl, 3/5 left to be eaten by John, who ate 25 before running out.
3/5 x = 25
x = 25 × 5/3 = 125/3 = 41 + 2/3
Or, Start with x muffins. Carl ate 2/5 x, leaving 3/5 x. John ate 25 with zero left over. So 3/5 x = 25.
(x - 2/5 x) - 25 = 0
3/5 x = 25
x = (5/3) × 25 = 125/3.
The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.
Step-by-step explanation:
1)The given equations are:
x − 2y = 6 ...(i)
3x − 6y = 0 ...(ii)
Putting x = 0 in equation (i) we get
=> 0 - 2y = 6
=> y = -3
x = 0, y = -3
Putting y = 0 in equation (i) we get
⇒x-2×0=6
⇒x=6
x = 6, y = 0
Use the following table to draw the graph
x 0 6
y -3 0
Plotting the two points A(0, -3) and B(6,0) equaion (1) can be drawn
Graph of the equation ..(ii)
3x - 6y = 0 ...(ii)
Putting x = 0 in equation (ii) we get
⇒3×0-6y=0
=> y = 0
x = 0, y = 0
Putting x = 2 in equation (2) we get
⇒3×2-6y=0
=> y = 1
x = 2, y = 1
Use the following table to draw the graph.
x 0 2
y 0 1
Draw the graph by plotting the two points O(0,0) and D(2,1) from table
We see that the two lines are parallel, so they won’t intersect
Hence there is no solution
2)
Answer:
i think this is the correct answer
Step-by-step explanation:
Simplifying
8x + -7y = 23
Solving
8x + -7y = 23
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '7y' to each side of the equation.
8x + -7y + 7y = 23 + 7y
Combine like terms: -7y + 7y = 0
8x + 0 = 23 + 7y
8x = 23 + 7y
Divide each side by '8'.
x = 2.875 + 0.875y
Simplifying
x = 2.875 + 0.875y
