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belka [17]
3 years ago
11

Instructions: Given the vertex of a quadratic function, find the axis

Mathematics
1 answer:
allsm [11]3 years ago
5 0

<u><em>The axis of symmetry is x = 5.</em></u>

In first place, every quadratic function can be expressed as follows:

f(x) = a*x² + b*x + c

where a, b and c are real numbers and a ≠ 0. This way of writing the quadratic function is called polynomial.

The graph of a quadratic function is a parabola. Every parabola is a symmetric curve with respect to a horizontal line called the axis of symmetry. That is, the axis of symmetry is an imaginary line that passes through the middle of the parabola and divides it into two halves that are mirror images of each other.

The point of intersection of the axis of symmetry with the parabola is called the vertex, and it divides the parabola into two branches. That is, the axis of symmetry always passes through the vertex of the parabola. The x-coordinate of the vertex is the equation of the axis of symmetry of the parabola.

Then, being the <em>vertex</em> of the quadratic function <em>(5,7)</em>, where the vertex on the x-axis has a value of 5 and on the y-axis a value of 7, <u><em>the axis of symmetry is x = 5.</em></u>

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The distance between 19 and -15 on a number line is 4?
Murrr4er [49]

Answer:

See explanation below.

Step-by-step explanation:

No.

The distance between 19 and 15 is 4. Both numbers are positive, 4 units apart.

The distance between -19 and -15 is also 4. Both numbers are negative, 4 units apart.

When you find the distance from 19 to -15, keep in mind that one number is positive, 19, and one number is negative, -15. The two numbers are on different side of zero on the number line.

Start at -15. -15 is 15 units to the left of zero. To get to 0, you need to go 15 units right. Now you need to go from 0 to 19. That is another 19 units right. Add 15 + 19 to get 34.

The distance from 19 to -15 on a number line is not 4. It is 34.

8 0
3 years ago
Two less than y is subtracted from x​
hram777 [196]

Answer: x- (y-2)

Step-by-step explanation:

Two less than y would be y-2,

Then you just subtract it from x

8 0
1 year ago
Require full steps working for this question
Ray Of Light [21]

I let the computer do the graphing.  

f(x) = x(x + 3)²(1 - x) / 3

We see obvious zeros at x=0, x=-3 and x=1.

f(x) = x(x + 3)²(1 - x) / 3

f(x) = x(x^2 + 6x + 9)(1 - x)/3

f(x) = x(x^2 + 6x + 9 - x^3 - 6x^2 - 9x)/3

f(x) = x(- x^3 - 5x^2 -3x +9)/3

f(x) = (-x^4 - 5x^3 -3x^2 +9x)/3

f'(x) = (-4x^3 - 15x^2 -6x + 9)/3

We know there's f'(-3)=0 so x+3 must be a factor here,

f'(x) = (x + 3) (-4x^2 - 3x + 3)

We get stationary points when x = -3 or

x = (-1/8)( 3 ± √(9 - 4(-4)(3))) =  (-3 ± √57)/8  about -1.3 and 0.6 which are a local minimum and maximum respectively.

f''(x) = (-12x^2 - 30x -6)/3 = -4x^2 - 10x - 2

f''(-3) = -4(9)+ 30 - 2 = -8

Concave Down, Negative.   (-3,0) is a local maximum.

f''((-3 - √57)/8) = -4(-1.3)^2 - 10(-1.3) - 2 = 4.24

Concave up, positive, a CUP

(-3 - √57)/8, f((-3 - √57)/8) ) is a minimum.

f''((-3 + √57)/8) = -4(.6)^2 - 10(.6) - 2 = -9.44

CDN, ( ((-3 + √57)/8), f((-3 + √57)/8) ) is a maximum.

I didn't evaluate f((-3 ±√57)/8) which are around -3 and 1 but I leave that calculation to you.

6 0
3 years ago
Answer with explanation please
Drupady [299]

Answer:

D. x>5

Step-by-step explanation:

3x  + 2 < 4x - 3 \\  = 3x - 4x <  - 3 - 2 \\  =  - x  <  - 5 \\ =  x > 5

7 0
2 years ago
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