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Maksim231197 [3]
3 years ago
15

Find the inverse function of y=3x-7

Mathematics
1 answer:
Studentka2010 [4]3 years ago
5 0

Answer:

Since g(f(x))=x g ( f ( x ) ) = x , f−1(x)=x3+73 f - 1 ( x ) = x 3 + 7 3 is the inverse of f(x)=3x−7 f ( x ) = 3 x - 7 .

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24x-12x^2=0 What is the result of this(please step by step)
Sav [38]
Okay..
12 x^2 = 24x

12x = 24

x= 2  and x=0

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5 0
3 years ago
Please answer the following
nikitadnepr [17]
The first part of the answer is 20x+9
Second part is 4a-6b
3 0
3 years ago
What is (3x9-6+3\10)
aliya0001 [1]
The order of operations says:
P arentheses 
E xponents
M ultiplication
D ivision
A ddition
S ubtraction

So first we will do 3 x 9 = 27.   (27 - 6 + 3 / 10) 
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PLSS HELP!! Pentagon JKLMN is similar to pentagon VWXYZ. What is the measurement of angle W?
Tamiku [17]

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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
If tanA+sinA=m and tanA-sinA=n.prove that m^2-n^2=4√mn
mash [69]

Let a=\tan A and b=\sin A. Then

m^2-n^2=(a+b)^2-(a-b)^2=(a^2+2ab+b^2)-(a^2-2ab+b^2)=4ab

\implies m^2-n^2=4\tan A\sin A

and

mn=(a+b)(a-b)=a^2-b^2

\implies4\sqrt{mn}=4\sqrt{\tan^2A-\sin^2A}

The expression under the square root can be rewritten as

\tan^2A-\sin^2A=\dfrac{\sin^2A}{\cos^2A}-\sin^2A=\sin^2A\left(\dfrac1{\cos^2A}-1\right)=\sin^2A(\sec^2A-1)

Recall that

\sin^2A+\cos^2A=1\implies\tan^2A+1=\sec^2A

so that

\tan^2A-\sin^2A=\sin^2A\tan^2A

and assuming \sin A>0 and \tan A>0, we end up with

4\sqrt{\tan^2A-\sin^2A}=4\tan A\sin A

so that

m^2-n^2=4\sqrt{mn}

as required.

5 0
2 years ago
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