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2 years ago

Which statement describes the solution(s) to the system of equations -6x -3y =12 and -12x -6y= -24?

Mathematics

1 answer:

pogonyaev2 years ago

4 0

Answer:

Step-by-step explanation:

i had the same question on my test lol

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The polygon is a regular nonagon (9-sides). What is the sum of the interior angles? What is the measurement for each angle?

lana66690 [7]

Divide the nonagon radially into 9 congruent, equilateral isosceles triangle. Each triangle has vertex angle of 360°/9 = 40°.
Interior angle of polygon = 180°-40° = 140°.
Sum of interior angles = 9(140°) = 1260°

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2 years ago

What is a segment bisector

ruslelena [56]

A segment bisector is a segment, ray, line, or plane that intersects a given segment at its midpoint.

For example, in the diagram shown, line SQ bisects segment PR because line SQ intersects segment PR at its midpoint which is Q.

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2 years ago

Solve −3x2 + 30x − 90 = 0. x equals 5 plus or minus 2i square root of 5 x equals 5 plus or minus i square root of 5 x equals 10

Tcecarenko [31]

The x in your equation is 16/5 or 3 1/5 or 3.2 if you want it simplified

5 0

2 years ago

Read 2 more answers

the ratio of students who walked home from school to the students who ride the bus home is 2.7. The number of the bus riders is

cupoosta [38]

Answer:

3.5

Step-by-step explanation:

If there are 9 students total and the ratio is 2:7 for walk home to ride bus then the answer would you would divide 2 from 7 which can be written as 7/2 then you would get your answer. Plus if the question says how many times the number... that means division:).

HOPE THIS HELPS!!:)

7 0

2 years ago

Solve question 3 for <br> 41 points

Sever21 [200]

Answer:

(2)

Step-by-step explanation:

Our logarithmic expression is: $ln(\frac{\sqrt{e} }{y^3} )$ .

Remember the logarithmic property that ln(a/b) = lna - lnb. So, we can write this as:

$ln(\frac{\sqrt{e} }{y^3} )=ln(\sqrt{e} )-ln(y^3)$

Also, we can write square roots as powers of one-half, so √e = $e^{1/2}$ . There's another log property that: $ln(a^b)=b*ln(a)$ . We can apply that here for both the √e and the y³:

$ln(\sqrt{e} )-ln(y^3)=\frac{1}{2} ln(e)-3ln(y)$

Finally, note that ln(e) is just 1, so we have:

$\frac{1}{2} ln(e)-3ln(y)=\frac{1}{2} -3ln(y)=\frac{1-6ln(y)}{2}$

The answer is thus (2).

<em>~ an aesthetics lover</em>

7 0

2 years ago