3 years ago

What’s is two plus the quotient of a number and five is the same as ten? As an equation?

Mathematics

1 answer:

Svet_ta [14]3 years ago

7 0

The equation for this is 2 + n/5 = 10, where n is the number

You might be interested in

Find surface area and 136. 224 236 248 oops I forgot -.-|||

xxMikexx [17]

Answer:

B, 224in2

It may get tedious but just find the area of each face and write them down

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

5, 3.1.24 f(x) = 3x² + 5; find f(x + 3) - [f(x) + 3]

Aleks [24]

Given that $f(x) = 3x^2 + 5$ , we have

$f(x + 3) = 3 (x + 3)^2 + 5 \\\\= 3 (x^2 + 6x + 9) + 5 \\\\= 3x^2 + 18x + 32$

so that

$f(x+3) - (f(x) + 3) = (3x^2 + 18x + 32) - (3x^2 + 8) \\\\= \boxed{18x + 24}$

3 0

2 years ago

A student correctly added the two two-digit numbers on the left of the board and got the answer 137. What answer will she obtain

Goryan [66]

Answer:

im sry but i need halppppp with this

Step-by-step explanation:

7 0

3 years ago

Help Find the circumference of this circle using 3 for 7. C ~ [?]

Nikitich [7]

Answer:

C = 84

Step-by-step explanation:

14 × 2 = 28

28 × 3 = 84

#CarryOnLearning 

6 0

3 years ago

Read 2 more answers

If 322c = 80+7, what is the value of c?

Damm [24]

Answer:

c = 3

Step-by-step explanation:

Using the rule of exponents

$(a^m)^{n}$ = $a^{mn}$

note that 32 = $2^{5}$ and 8 = 2³ , then

$32^{2c}$ = $8^{c+7}$ , becomes

$(2^5)^{2c}$ = $(2^3)^{c+7}$

$2^{10c}$ = $2^{3c+21}$

Since the bases on both sides are equal, both 2, then equate the exponents

10c = 3c + 21 ( subtract 3c from both sides )

7c = 21 ( divide both sides by 7 )

c = 3

4 0

3 years ago