Unit rate 5 breaks in 8 hours
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We know that there are 100 cm in 1 m. We can convert 0.75 m to cm by multiplying by 100 to give us:
Therefore the path before the addition is 75 cm wide.
Mr. Kassel added 20 cm of blocks on each side of the path, meaning that the added width is actually 40 cm total (20 on each side, and there are 2 sides).
So we need to add 40 cm to the original 75 cm:
So now we have the width of the path in cm, the question asks for the width in meters. We can do this by dividing the width in cm by 100 to get the width in meters:
Now we know that the new width of the path is 1.15 m.
Therefore the path before the addition is 75 cm wide.
Mr. Kassel added 20 cm of blocks on each side of the path, meaning that the added width is actually 40 cm total (20 on each side, and there are 2 sides).
So we need to add 40 cm to the original 75 cm:
So now we have the width of the path in cm, the question asks for the width in meters. We can do this by dividing the width in cm by 100 to get the width in meters:
Now we know that the new width of the path is 1.15 m.