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Arlecino [84]
3 years ago
8

Can someone help me with this

Mathematics
1 answer:
Sergio [31]3 years ago
8 0

Answer:

Infenitely many solutions

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An aquarium has a base in the shape of a trapezoid. The base is 100
Nat2105 [25]

Answer:

Volume = 210L

Step-by-step explanation:

Given

Base:

Front = 100cm

Back = 50cm

Width = 40cm

Height = 70cm

Required

Determine the volume (in litres)

First, we need to calculate the area;

Base on the parameters given, we have:

Area = \frac{1}{2}(Front + Back) * Width

Area = \frac{1}{2}(100cm + 50cm) * 40cm

Area = \frac{1}{2}(150cm) * 40cm

Area = 75cm * 40cm

Area = 3000cm^2

Volume = Area * Height

Volume = 3000cm^2 * 70cm

Volume = 210000cm^3

1cm^3 = 0.001L

So:

Volume = 210000 * 0.001L

Volume = 210L

4 0
4 years ago
A byciclist travels 1 mile in 5 minutes. If m represents minutes what does the expression m/5 represents
earnstyle [38]

Answer:

It represents 5 miles in 5 minutes

Step-by-step explanation:

Because, if the bycicleist travels 1 mile in 1 minute, in 5 minutes he traveled 5 miles

4 0
3 years ago
It takes 63 minutes for 4 people to paint 9 walls.
alukav5142 [94]

Answer:  7 people need 16 minutes to paint 4 walls.

Step-by-step explanation:

Since we have given that it takes 63 minutes to paint 9 walls ,

So, we will apply "time and work formula" i.e.

\frac{M_1\times D_1\times H_1}{W_1}=\frac{M_2\times D_2\times H_2}{W_2}

where,

H denotes number of hours or minutes,

D denotes number of days

M denotes number of men

W denotes work done them,

So, we need to calculate number of minutes for 7 people to paint 4 walls,

\frac{63\times 4}{9}=\frac{M\times 7}{4}\\\\7\times 4=\frac{M\times 7}{4}\\\\16=M

So, 7 people need 16 minutes to paint 4 walls.

6 0
3 years ago
Read 2 more answers
Which explains whether Trina is correct
dangina [55]

Answer:

because the two sides of the equation are equivalent

Step-by-step explanation:

6 0
3 years ago
14 - 2(3p + 1) = 6(4/p)
GuDViN [60]
Is it divide after the equal sign? I will text you on message. follow me
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4 years ago
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