<span>N(t) = 16t ; Distance north of spot at time t for the liner.
W(t) = 14(t-1); Distance west of spot at time t for the tanker.
d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t.
Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is
N(t) = 16t
Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is
W(t) = 14(t-1)
The distance between the 2 ships is easy. Just use the pythagorean theorem. So
d(t) = sqrt(N(t)^2 + W(t)^2)
If you want the function for d() to be expanded, just substitute the other functions, so
d(t) = sqrt((16t)^2 + (14(t-1))^2)
d(t) = sqrt(256t^2 + (14t-14)^2)
d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) )
d(t) = sqrt(452t^2 - 392t + 196)</span>
Answer: 348
Step-by-step explanation:
Given : Total employees work = 725
Proportion of employees are post graduate = 52%
Proportion of employees are not post graduate = 100%-52% = 48%
The number of employees were not post graduate = 48% of 725
= 0.48 x 725
= 348
Hence, the number of employees were not post graduate = 348
Answer:
y = 30x + 20
Step-by-step explanation:
y = mx + b
find b
b=20
find m
m=30
Answer:
430 minutes total
Step-by-step explanation:
Mo had 35 minutes sessions 14 times. You have to multiply 35 by 14 to get the answer which is 430 minutes.
Answer:
??? No solution???
Step-by-step explanation:
1.9x106=201.4
201.4x25000=5035000
5035000=5.035x10^6
