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Novosadov [1.4K]
3 years ago
8

What’s 44/24 As a mixed number

Mathematics
2 answers:
Zina [86]3 years ago
7 0

Answer:

1 5/6

Step-by-step explanation:

Gnesinka [82]3 years ago
5 0
1 5/11

That’s reduced to the lowest point
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A sum of Rs 1,50,000 amounts to Rs 2,62,500 at a
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3 0
3 years ago
4х – 9у – 2 = 0 <br>12х - 5у + 38 = 0 <br>answer in x and y intercept​
garri49 [273]

Answer:

x=5

y=2

Step-by-step explanation:

-3(4х – 9у – 2 = 0)

=-12x+27y+6

12х - 5у + 38    

-12x+27y+6

22y=44

y=2

x:

4x-9(2)-2=

=4x-20

4x=20

x=5

3 0
3 years ago
Can you guys give me 3 examples of the inverse property
Irina-Kira [14]

Of multiplication or addition?


3 0
3 years ago
A spherical ball with a volume of 972π in.3 is packaged in a box that is in the shape of a cube. The edge length of the box is e
mojhsa [17]

Answer:

V = 4/3 x pi x r^3

972 x pi= 4/3 x pi x r^3

729 = r^3

The cubic root of 729 is 9 because 9 x 9 x 9 = 729.

The radius is 9 inches, and the diameter is 18 inches.

The volume of the box is 18 in x 18 in x 18 in or 5832 in.³.

Step-by-step explanation:

7 0
3 years ago
There are 15 students in the 8th grade. The students are randomly placed into three different algebra classes of 5 students each
xeze [42]

Answer:

The probability is   \frac{6}{91} ≅ 0.0659

Step-by-step explanation:

Let's analyze the question.

There are 15 students in the 8th grade.

The students are randomly placed into three different algebra classes of 5 students each.

We are looking for the probability that Trevor, Terry and Evan will be in the same algebra class.

One possible way to solve this question is to think about the product probability rule.

We can use it because we are in an equiprobable space. (And  also the events are independent).

Let's set for example a class for Evan.

The probability that Evan will be in a class is 1

Then for Terry there are 4 places out of 14 that puts Terry in the Evan's class.

We write 1.\frac{4}{14}

Finally for Trevor there are 3 places out of the remaining 13 that puts Trevor in the same class with Evan and Terry.

Using the product rule we write :

1.\frac{4}{14}.\frac{3}{13}=\frac{6}{91}

The probability of the event is \frac{6}{91} ≅ 0.0659

5 0
3 years ago
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