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Evgen [1.6K]
3 years ago
12

Which mathematical equation represents the solution for k in the equation h + 3 = jk + 6k ?

Mathematics
1 answer:
Tomtit [17]3 years ago
5 0

Answer:

The answer is<u> D.</u> h+3/j+6.

Step-by-step explanation:

Given:

The equation h + 3 = jk + 6k.

Now, to get the mathematical expression.

h + 3 = jk + 6k

So, taking k common on R.H.S we get:

h + 3 = k(j + 6)

Then, dividing both sides by j+6  we get:

\frac{h+3}{j+6} =k

Thus,

k=\frac{h+3}{j+6}

Therefore, the answer is D. h+3/j+6.

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Answer:

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7 mm:1,000 mm                      Divide both sides by 7


1 mm:142 6/7 mm - This is the scale that Tess used.

Step-by-step explanation:


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3 years ago
Use the model to solve the equation.
Alika [10]
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4 years ago
What word describes the slopes of the line
grin007 [14]

Answer:

Positive

Step-by-step explanation:

There are a couple ways we can go about this.

First, we can see that as x increases, so does y, so that means its positive

For perspective, if x is the amount of time and y is the number of sales, we can see that the sales are going up and not going down or staying at the same place

If you wanna check your work on that, you can plot two points and find the slope using y1-y1/x1-x2 and the slope will be positive.

We can also use the process of elimination, we know it can't be zero because it's not a straight, horizontal line and we know its not undefined because it isn't a straight vertical line, so it's between negative and positive, and since the line is going up, that means that it's positive.

4 0
3 years ago
Find the interest rate for ​$9000 deposit accumulating to ​$9889​, compounded annually for 5 years.
stellarik [79]

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7 0
3 years ago
7- a. What is the radius of the circle with center (3,10) that passes through (12,12)?
loris [4]

Answer: a. Radius of circle = \sqrt{85}

b. The equation of this circle : (x-3)^2+(y-10)^2=85

Step-by-step explanation:

Given : Center of the circle = (3,10)

Circle is passing through (12,12).

a. To find the radius we apply distance formula (∵ Radius is the distance from center to any point ion the circle.)

Radius of circle = \sqrt{(12-3)^2+(12-10)^2}

Radius of circle = \sqrt{(9)^2+(2)^2}=\sqrt{81+4}=\sqrt{85}

i.e. Radius of circle = \sqrt{85}

b. Equation of a circle = (x-h)^2+(y-k)^2=r^2 , where (h,k)=Center and r=radius of the circle.

Put the values of (h,k)= (3,10) and r= \sqrt{85} , we get

(x-3)^2+(y-10)^2=(\sqrt{85})^2

(x-3)^2+(y-10)^2=85

∴  The equation of this circle :(x-3)^2+(y-10)^2=85

6 0
3 years ago
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