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kipiarov [429]
2 years ago
11

How many solutions does this equation have? 6x + 2 = x + 2

Mathematics
1 answer:
exis [7]2 years ago
7 0
<h2>Hey there! </h2><h2>\bold{SUBTRACT\ x\ to\ BOTH\ SIDES}</h2><h2>\bold{6x+2-x=x+2-x}</h2><h2>\bold{Cancel \ out: x -x\ because\ it\ us\ 0}</h2><h2>\bold{Keep: 6x-x\ because\ that\ helps\ solve\ for\ x}</h2><h2>\bold{6x-x =5x}</h2><h2>\bold{New\ equation: 5x+2=2}</h2><h2>\bold{SUBTRACT\ 2\  to\ BOTH\ SIDES}</h2><h2>\bold{5x+2-2=2-2}</h2><h2>\bold{Cancel\ out: 2-2\ (on\ the\ LEFT\ SIDE)\ because\ that\ gives\ you\ 0 }</h2><h2>\bold{Keep: 2-2\ (on\ the\ RIGHT\ SIDE)\ because\ it\ helps\ us\ solve\ for\ x}</h2><h2>\bold{2-2=0}</h2><h2>\bold{New\ equation: 5x=0}</h2><h2>\bold{DIVIDE\ 5\ to\ BOTH\ SIDES}</h2><h2>\bold{\dfrac{5x}{5}=\dfrac{0}{5}}</h2><h2>\bold{Cancel\ out: \dfrac{5}{5} \ because\ it\ gives\ you\ 1}</h2><h2>\bold{Keep: \dfrac{0}{5}\ because\ it\ helps\ solve\ for\ x}</h2><h2>\bold{x=\dfrac{0}{5}}</h2><h2>\boxed{\boxed{\bold{Answer: \boxed{\bold{x=0}} }}}\huge\checkmark</h2><h2>Good luck on your assignment and enjoy your day! </h2><h3>~\frak{LoveYourselfFirst:)}</h3>
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