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3 years ago

suppose that y varies directly as x . if y is 24 when x is 6, find the constant of variation and the direct variation equation

Mathematics

1 answer:

Reika [66]3 years ago

3 0

Answer:

Step-by-step explanation:

Direct variation can be modeled by y = kx where k is the constant of variation!

So to solve for k all we need to do is substitute in the value for y and x that are given.

So according to the problem y = 24 when x = 6

24 = 6k

Divide both sides by 6

k = 4

So the constant of variation is 4

The direct variation equation would then be

y = 4x

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2 years ago

∠R and ∠S are complementary. If m∠R = (2x+7) and m∠S = (4x - 13), find m∠R

____ [38]

Answer:

m∠R = 39 degrees

Step-by-step explanation:

As complementary angles add up to 90 degrees, we can set up an equation to get x then find the measure of ∠R:

m∠R + m∠S = 90

2x+7+4x-13=90

6x+7-13=90

6x-6=90

6x=96

x=16

Since m∠R = (2x+7), 2x+7 would be 2(16)+7 or 39 degrees. So in conclusion, m∠R = 39 degrees

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3 years ago

Read 2 more answers

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Reptile [31]

Answer:

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6 0

3 years ago

Linda purchase a prepaid phone card for $30. Long distance calls cost $.17 a minute using this card when do use her card. Linda

balandron [24]

Answer: her call lasted for 44 minutes

Step-by-step explanation:

Linda purchase a prepaid phone card for $30. This means that the credit on her card is $30.

Long distance calls cost $0.17 each. Linda use her card only to make a long distance call. Assuming she made a total of x minutes of long distance calls, the cost would be $0.17x. The amount remaining on her card will be

30 - 0.17x

if the remaining credit on her card is $22.52, the number of minutes,x that the call lasted will be

22.52 = 30 - 0.17x

0.17x = 30 - 22.52

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7 0

3 years ago

If triangle ABC is similar to triangle DEC, find the values of x and y.

Mumz [18]

The values are x=8 and y=35, if the given ΔABC and ΔDEC are equal, it is obtained by Pythagoras theorem.

Step-by-step explanation:

The given are,

From ΔABC,

AB= 6

BC= 10

AC = x

From ΔDEC,

CD= 28

DE= 21

CE = y

Step:1

Pythagoras theorem from ΔABC,

$BC^{2}=AB^{2} + AC^{2}$ ...............(1)

Substitute the values,

$10^{2}$ = $6^{2}$ + $AC^{2}$

100 = 36 + $AC^{2}$

$AC^{2}$ = 100 - 36

= 64

AC = $\sqrt{64}$

AC = 8

AC = x = 8

Step:2

Pythagoras theorem for ΔDEC,

$CE^{2} = CD^{2} + DE^{2}$ ................(2)

From the values,

$CE^{2}$ = $28^{2}$ + $21^{2}$

$CE^{2}$ = 784 + 441

= 1225

CE = $\sqrt{1225}$

CE = 35

CE = y = 35

Result:

The values are x=8 and y=35, if the given ΔABC and ΔDEC are equal.

5 0

2 years ago