So if the larger pennant is 18”x 9” x 9”
and the smaller one is about the same in similar size, with the bass measuring 6”..
I would take the bases of both and divide them 6” smaller base goes in to the 18” larger base 3 times so I take the sides 9” and see what goes into it 3 times 9 divided by 3 is 3 .. so the sides would be 3 making the smaller triangle 6x3x3
Answer:
Thus, it is possible to erect a pole at a point p on the boundary of the park at distances 5m and 12m respectively from gates B and A.
Step-by-step explanation:
Let P be the required location of pole .
A and B are the two gates.
Let the distance of pole at p from gate be 'x' meters
i.e. PB = x m
•°• AP = (x + 7)m and AB = 13 m
•°• AP² + BP² = AB² => (x +7)² + x =13²
Rejecting x =-12, we get x = 5
•°• PB = 5m
and
AP = 12m
(I hope this helped :)
