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2 years ago

Answer to this please? There are multiple I believe.

Mathematics

2 answers:

Vera_Pavlovna [14]2 years ago

5 0

As per me only 1 follows - SAS

Roman55 [17]2 years ago

5 0

Answer:

nahi pata bhai

Step-by-step explanation:

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Amount of sugar in a sugar bowl is 0.75 cups

Mariana [72]

I equals 70 grams cup because

4 0

3 years ago

32 = 4(n – 5) and -s + 11 = 17 please solved Both of the following

valina [46]

Answer:

n=13 s=-6

Step-by-step explanation:

Hope this helps :)

4 0

2 years ago

Read 2 more answers

Find the least common denominator for these two rational expressions 7/n^2 -8/7n

lianna [129]

Answer:

7n²

Step-by-step explanation:

7/n² - 8/7n

Least common multiple will be the least common denominator

L.C.M = 7n²

Dividing the L.C.M by denominators and multiplying with numerators;

((7×7) - (n×8))/7n²

= (49 - 8n)/7n²

7n² is the least common denominator

8 0

3 years ago

Cos-1 25²-52 52 -37 2625 )(37)

34kurt

Answer:

Step-by-step explanation:

i do not know

4 0

3 years ago

Given limit f(x) = 4 as x approaches 0. What is limit 1/4[f(x)]^4 as x approaches 0?

stepladder [879]

Answer:

$\displaystyle 64$

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Limit Rule [Variable Direct Substitution Exponential]: $\displaystyle \lim_{x \to c} x^n = c^n$

Limit Property [Multiplied Constant]: $\displaystyle \lim_{x \to c} bf(x) = b \lim_{x \to c} f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \lim_{x \to 0} f(x) = 4$

Step 2: Solve

Rewrite [Limit Property - Multiplied Constant]: $\displaystyle \lim_{x \to 0} \frac{1}{4}[f(x)]^4 = \frac{1}{4} \lim_{x \to 0} [f(x)]^4$
Evaluate limit [Limit Rule - Variable Direct Substitution Exponential]: $\displaystyle \lim_{x \to 0} \frac{1}{4}[f(x)]^4 = \frac{1}{4}(4^4)$
Simplify: $\displaystyle \lim_{x \to 0} \frac{1}{4}[f(x)]^4 = 64$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

Book: College Calculus 10e

3 0

2 years ago