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2 years ago

Answer to this please? There are multiple I believe.

Mathematics

2 answers:

Vera_Pavlovna [14]2 years ago

5 0

As per me only 1 follows - SAS

Roman55 [17]2 years ago

5 0

Answer:

nahi pata bhai

Step-by-step explanation:

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Am solving this problem correct

cestrela7 [59]

A) The degree of the first term is... 1
$first \ term = 3t$
The degree of the second term is... 2
$second \ term = t^2$
The degree of the third term is... 4
$third \ term = t^4$

b) The leading term of the polynomial is... 7t⁴
The leading coefficient of the polynomial is... 7

c) The degree of the polynomial is... 4

6 0

3 years ago

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Write the Equation of the line that is parralel to the linear equation in question 1 and passes through the point (3,7)

BlackZzzverrR [31]

Where’s question 1? And the question

4 0

3 years ago

As a salesperson, you are paid $52 per week plus $3 per sale. This week you want your pay to be at least $100. Write an inequali

ArbitrLikvidat [17]

Answer:

s≥16

Step-by-step explanation:

3s+52≥100

3s≥100-52

3s≥48

s≥48/3

s≥16

6 0

3 years ago

Solve the equation 6w2 – 7w – 20 = 0.

azamat

For this case we have the following quadratic equation:

$6w ^ 2-7w-20 = 0$

Where:

$a = 6\\b = -7\\c = -20$

Its roots will be given by:

$w = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}\\w = \frac {- (- 7) \pm \sqrt {(- 7) ^ 2-4 (6) (- 20)}} {2 (6)}\\w = \frac {7 \pm \sqrt {49 + 480}} {12}\\w = \frac {7 \pm \sqrt {529}} {12}\\w = \frac {7 \pm23} {12}$

The roots are:

$w_ {1} = \frac {7 + 23} {12} = \frac {30} {12} = \frac {15} {6} = \frac {5} {2}\\w_ {2} = \frac {7-23} {12} = \frac {-16} {12} = - \frac {8} {6} = - \frac {4} {3}$

Answer:

$w_ {1} = \frac {5} {2}\\w_ {2} = - \frac {4} {3}$

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3 years ago

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How can you check the answer when a division problem has a remainder

slavikrds [6]

Mathpapa.com is the website to use

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3 years ago

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