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steposvetlana [31]
2 years ago
10

Answer to this please? There are multiple I believe.

Mathematics
2 answers:
Vera_Pavlovna [14]2 years ago
5 0
As per me only 1 follows - SAS
Roman55 [17]2 years ago
5 0

Answer:

nahi pata bhai

Step-by-step explanation:

n

a

h

i

p

a

t

a

b

r

o

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Which ordered pair is a solution to the equation y = 6x - 4? The answer choices are A) (2, 1)
user100 [1]
B

Substitute the first number for x and see which one it is

6 x 1 - 4 = 2
3 0
2 years ago
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IGHT im pretty stupid right now but can you help me out?
matrenka [14]

Answer:

complementary

Step-by-step explanation:

i went to school.

8 0
3 years ago
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Solve for x.<br><br> 2(4x - 1) + 3(3 - 2x) = 0<br><br> x = -4<br> x = -7/2<br> x = -4/3<br> x = -7/6
lara [203]
The correct answer: x=-7/2
Hope this help!!!
7 0
2 years ago
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How can Kendra determine if the function is actually linear?
pashok25 [27]

Answer:

D. She can check to see if the rate of change between the first two ordered pairs is the same as the rate of change between the first and last ordered pairs.

Step-by-step explanation:

Find the rate of change between first two ordered pairs and the second two ordered pairs:

1. Points (2,4) and (3,9). Rate of change:

\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{9-4}{3-2}=\dfrac{5}{1}=5

2. Points (3,9) and (4,16). Rate of change:

\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{16-9}{4-3}=\dfrac{7}{1}=7

The rate of change for the linear function must the same for each two points on the graph of the function. In this case, the reate of change differs, so this function is not linear and correct option is D.

8 0
3 years ago
Read 2 more answers
A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet
Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

L_{1} = 2W_{1}

Also, the area of the walkway of 2 feet wide is 448:

W_{2} = 2 ft

A_{T} = W_{2}*L_{2} = 448 ft^{2}

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

A_{T} = A_{1} + A_{w}    (1)          

The area of the pool is given by:

A_{1} = L_{1}*W_{1}        

A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}  (2)          

And the area of the walkway is:

A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}    (3)          

Where the length of the bigger rectangle is related to the lower rectangle as follows:                  

L_{2} = 4 + L_{1} = 4 + 2W_{1}   (4)        

By entering equations (4), (3), and (2) into equation (1) we have:

A_{T} = A_{1} + A_{w}

A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}                

448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}            

224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}

224 = W_{1}^{2} + 8 + 6W_{1}

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

L_{1} = 2W_{1} = 2*12 ft = 24 ft

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!                                                                                          

8 0
2 years ago
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