A runner is jogging in a straight line at a
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Let x be a discrete binomial random variable that measures the number of successes in n trials.
Let p = 0.4 be the probability of success, that is, the probability that a deer has the aforementioned type of tick.
So the probability that 124 deer or less have this type of tick is calculated using the probability formula for a binomial distribution.
P (X <= x) = sum from x = 0 to x = 124 of (300! / ((X! * (300-x)!)) * (P ^ x) * (1-p) ^ n-x.
Finally the probability is 0.7030
Below is an image with the formula used and the result
Let p = 0.4 be the probability of success, that is, the probability that a deer has the aforementioned type of tick.
So the probability that 124 deer or less have this type of tick is calculated using the probability formula for a binomial distribution.
P (X <= x) = sum from x = 0 to x = 124 of (300! / ((X! * (300-x)!)) * (P ^ x) * (1-p) ^ n-x.
Finally the probability is 0.7030
Below is an image with the formula used and the result
Answer: The required expression she is on after d days is
Step-by-step explanation:
Since we have given that
Page number at which she is = 88
Number of pages she will read every day = 20
Let the number of days be 'x'.
According to question, it becomes
Hence, the required expression she is on after d days is