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astraxan [27]
3 years ago
15

What is the center of the equation X^2+y^2-4x-8y-16=0

Mathematics
1 answer:
Mice21 [21]3 years ago
6 0
                                            x² + y² - 4x - 8y - 16 = 0
                                                                      + 16 + 16
                                                   x² + y² - 4x - 8y = 16
                                                   x² - 4x + y² - 8y = 16
                                  (x² - 4x + 4) + (y² - 8y + 16) = 16 + 4 + 16
                   (x² - 2x - 2x + 4) + (y² - 4y - 4y + 16) = 20 + 16
[x(x) - x(2) - 2(x) - 2(-2)] + [y(y) - y(4) - 4(y) - 4(4)] = 36
                 [x(x - 2) - 2(x - 2)] + [y(y - 4) - 4(y - 4)] = 36
                                   (x - 2)(x - 2) + (y - 4)(y - 4) = 36
                                                  (x - 2)² + (y - 4)² = 36
                                                    36           36        36
                                          ¹/₃₆(x - 2)² + ¹/₃₆(y - 4)² = 1
Center: (2, 4)
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Please I need hep, get free brainly :D
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Step-by-step explanation:

<u>Formula:</u>

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The radius is 1/2 of the diameter.

Since 1/2 of 16 is 8, 8 is our radius.

<u>Substitute:</u>

a = 3.14(8)^{2}

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2 years ago
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natima [27]

Answer:

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Step-by-step explanation:

It often works well to follow problem directions. A graph is attached, showing the one solution to be (4, 1).

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3 years ago
Find what x is? 5×3&gt;4+8+x a good help for your brain! ​
MaRussiya [10]

Answer:

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melamori03 [73]

Answer:

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2 years ago
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3/4 (x-12)=12<br> And 3/4y-12=12
lianna [129]
3/4 (x-12)=12
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*3/4     *3/4
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and 

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3/4y = 24
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3 years ago
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