What is the center of the equation X^2+y^2-4x-8y-16=0
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Using Pythagorean theorem, the student walked 53.58 meters more compared to the total displacement from the starting point.
If a student walks 100 meters north, then 100 meters west, then the path he travels resembles the sides of a right triangle (see attached photo).
Using Pythagorean theorem, we can solve for the total displacement from the starting point to the end point.
c^2 = a^2 + b^2
where c is the total displacement from the starting point to the end point
a is the distance he walks up north
b is the distance he walks to the west
c^2 = 100^2 + 100^2
c^2 = 10,000 + 10,000
c^2 = 20,000
c = 141.42 meters
Comparing the total distance the student walked and the total displacement from the starting point to the end point by subtraction.
100 meters + 100 meters - 141.42 meters = 53.58 meters
Learn more about Pythagorean Theorem here: brainly.com/question/343682
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This how you answer these questions. Try Answering the other 4. you Should get
2a. X=10.9
2b. C=47/5 or 9.4
3a. X=32.6
3b. X=55.7
I hope these helped
2a. X=10.9
2b. C=47/5 or 9.4
3a. X=32.6
3b. X=55.7
I hope these helped