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3 years ago

Which of the following functions is non-linear?

Mathematics

2 answers:

Brut [27]3 years ago

5 0

The one that is non-linear is D

Dvinal [7]3 years ago

3 0

The answer is D. That is the non linear function!

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a 2 1/2m board is to be used for making shelves,each using up 5/6m of board. Does he have enough board left to make another shel

Hunter-Best [27]

I dont think so because if you multiply 2 1/2 by 5/6 you would get 2 1/12 which means that you can make the first shelf but you would need to subtract 2 1/2 minus 2 1/12 and you would get 5/12. And 5/12 is not the same as 4/5

Hope this helps!!! Name me brainliest please!

6 0

3 years ago

thank you for hurrying here is the very last one Explain how you would find the perimeter of this triangle.

Lena [83]

Step-by-step explanation:

Use the method of TOA CAH SOH.

$tan(51.3) = \frac{opp}{adj} \\ \tan(51.3) = \frac{u}{4} \\ u = 4 \tan(51.3)$

$cos(51.3) = \frac{adj}{hypo} \\ \cos(51.3) = \frac{4}{v} \\ v \cos(51.3) = 4 \\ v = \frac{4}{ \cos(51.3) }$

Perimeter of triangle = Sum of all sides =

$u \: + \: v + 4$

5 0

3 years ago

Read 2 more answers

Can anyone help me find the coordinates (?,?) given that the shape is a parallelogram? (15 points)

xxTIMURxx [149]

The missing coordinates of the parallelogram is (m + h, n).

Solution:

Diagonals of the parallelogram bisect each other.

Solve using mid-point formula:

$$\text{Midpoint} =\left( \frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right )$

Here $x_1=m, y_1=n, x_2=h, y_2=0$

$$=\left( \frac{m+h}{2}, \frac{n+0}{2}\right )$

$$\text{Midpoint} =\left( \frac{m+h}{2}, \frac{n}{2}\right )$

<u>To find the missing coordinate:</u>

Let the missing coordinates by x and y.

Here $x_1=0, y_1=0, x_2=x, y_2=y$

$$\text{Midpoint}=\left( \frac{0+x}{2}, \frac{0+y}{2}\right )$

$$\left( \frac{m+h}{2}, \frac{n}{2}\right )=\left( \frac{0+x}{2}, \frac{0+y}{2}\right )$

$$\left( \frac{m+h}{2}, \frac{n}{2}\right )=\left( \frac{x}{2}, \frac{y}{2}\right )$

Now equate the x-coordinate.

$$ \frac{m+h}{2}=\frac{x}{2}$

Multiply by 2 on both sides of the equation, we get

m + h = x

x = m + h

Now equate the y-coordinate.

$$\frac{n}{2} = \frac{y}{2}$

Multiply by 2 on both sides of the equation, we get

n = y

y = n

Hence the missing coordinates of the parallelogram is (m + h, n).

5 0

3 years ago

The height of Josie's dog is 11 1/4 inches to the nearest quarter inch and 11 inches to the nearest half inch. Which measurement

goldenfox [79]

Dear Kellyeasterday, 11 1/4 inches is more precise.

5 0

3 years ago

Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2

Andre45 [30]

For this case, we must indicate which of the given functions is not defined for $x = 0$

By definition, we know that:

$f (x) = \sqrt {x}$ has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

$y = \sqrt {x-2}$ is not defined, the term inside the root is negative when $x = 0$ .

While $y = \sqrt {x + 2}$ if it is defined for $x = 0.$

$f(x)=\sqrt[3]{x}$ , your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

$y = \sqrt [3] {x-2}$ with x = 0: $y = \sqrt [3] {- 2}$ is defined.

$y = \sqrt [3] {x + 2}$ with x = 0: $y = \sqrt [3] {2}$ in the same way is defined.

Answer:

$y = \sqrt {x-2}$

Option b

6 0

3 years ago