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balandron [24]
2 years ago
8

How do i solve for this?

Mathematics
1 answer:
vodka [1.7K]2 years ago
5 0

Answer:

see explanation

Step-by-step explanation:

(16)

The mid segment ZW is half the sum of the parallel bases

ZW = \frac{38+20}{2} = \frac{58}{2} = 29

(17)

The lower base angles are congruent , so

∠ UYX = ∠ VXY = 35°

(18)

Any lower base angle is supplementary to any upper base angle , then

∠ VUY = 180° - ∠ UYX = 180° - 35° = 145°

(19)

\frac{UV+XY}{2} = ZW

\frac{3x-1+7x+1}{2} = 10 ( multiply both sides by 2 to clear the fraction )

10x = 20 ( divide both sides by 10 )

x = 2

Then

XY = 7x + 1 = 7(2) + 1 = 14 + 1 = 15

(20)

The legs are congruent , so

UY = VX

5a - 6 = 3a + 2 ( subtract 3a from both sides )

2a - 6 = 2 ( add 6 to both sides )

2a = 8 ( divide both sides by 2 )

a = 4

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Vika [28.1K]

Answer:

Well, for one thing I can't read the image--it's too small!

But I know these problems well. If I am correct, this is a spinner probability problem.

Your spinner appears to have 5 sectors, all equal in area, therefore making their probability equal.

So each of those has a prob of 1/5 in the scheme of things.

To find the combonational probability below, multiply the prob of each outcome together to find each.

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3 years ago
Find the volume of a pyramid with a square base, where the side length of the base is 10.6\text{ in}10.6 in and the height of th
Setler [38]

Answer:

460.7

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A proportional relationship betweeof potatoes (x) and the price in dollars (y) is graphed, and the ordered pair (4, 3) is on the
CaHeK987 [17]
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7 0
3 years ago
Gary is making a casserole but only needs 1/3 of the original serving size. If the number of servings Gary needs is 4, how many
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Answer:

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✔ x/3 = 4

How many servings did the original recipe make?

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Step-by-step explanation:

Hope this helps!

7 0
2 years ago
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The shaded sector above covers 1/3 of the circle. If the radius of the circle above is 3 cm, what is the area of the sector in t
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Given:

The shaded sector above covers \dfrac{1}{3} of the circle.

Radius of the circle = 3 cm

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Substituting r=3, we get

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It is given that the shaded sector above covers \dfrac{1}{3} of the circle.

The area of shaded sector =\dfrac{1}{3}A

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3 years ago
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