How do i solve for this?
1 answer:
Answer:
see explanation
Step-by-step explanation:
(16)
The mid segment ZW is half the sum of the parallel bases
ZW = =
= 29
(17)
The lower base angles are congruent , so
∠ UYX = ∠ VXY = 35°
(18)
Any lower base angle is supplementary to any upper base angle , then
∠ VUY = 180° - ∠ UYX = 180° - 35° = 145°
(19)
= ZW
= 10 ( multiply both sides by 2 to clear the fraction )
10x = 20 ( divide both sides by 10 )
x = 2
Then
XY = 7x + 1 = 7(2) + 1 = 14 + 1 = 15
(20)
The legs are congruent , so
UY = VX
5a - 6 = 3a + 2 ( subtract 3a from both sides )
2a - 6 = 2 ( add 6 to both sides )
2a = 8 ( divide both sides by 2 )
a = 4
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Answer:
Any points in the shaded region including (2,-2) and (-3,-8)
Step-by-step explanation:
Convert the line into slope intercept form and graph it.
2x-y > 1 becomes -y>1-2x. Divide both sides by -1 and you get y<2x-1. Graph it with the shaded area on the right and a dashed line.
Any point which falls within the shaded red of the graph is a solution. No points on the line since it is not equal to (its dashed) are solutions. Check the location of your points to verify that they fall within this area.
(-3, -8) ---Yes
(-1, -3) ---No
(0, 5) --- No
(1, 6) --- No
(2, -2) ---Yes
