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serious [3.7K]
3 years ago
11

Someone please help !!!!

Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
8 0
I believe the answer is A
AnnZ [28]3 years ago
6 0
It is A. when you synthetic divide you end up underneath 2 7 0. the 0 is the remainder. the other makes 2x+7
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The sum of twice a number and 8 is 44. what's the number? show your work.
mezya [45]

Answer:

18

Step-by-step explanation:

We can work backwards with this and take 44-8=36

Then we divide it by two and thats 18

3 0
2 years ago
Please help giving brainliest please
Serhud [2]

Answer:

$87025

Step-by-step explanation:

Net worth is assests minus liabilities

4 0
2 years ago
You are in charge of purchasing donuts and chocolate milk for a school activity. Find the cost of donuts and chocolate milk at y
inna [77]
An equation in standard form looks like Ax + By = C.

Let C = 80

Take it from here.
5 0
3 years ago
Write an expression that is equivalent to 4(w+3) -2
damaskus [11]

Steps to solve:

4(w + 3) - 2

~Disribute

4w + 12 - 2

~Combine like terms

4w + 10

Best of Luck!

8 0
2 years ago
Consider a Poisson distribution with μ = 6.
bearhunter [10]

Answer:

a) P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}

b) f(2) = 0.04462

c) f(1) = 0.01487

d) P(X \geq 2) = 0.93803

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of successes

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

In this question:

\mu = 6

a. Write the appropriate Poisson probability function.

Considering \mu = 6

P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}

b. Compute f (2).

This is P(X = 2). So

P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}

P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462

So f(2) = 0.04462

c. Compute f (1).

This is P(X = 1). So

P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}

P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487

So f(1) = 0.01487.

d. Compute P(x≥2)

This is:

P(X \geq 2) = 1 - P(X < 2)

In which:

P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}

P(X = 0) = \frac{e^{-6}*6^{0}}{(0)!} = 0.00248

P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487

P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462

Then

P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.00248 + 0.01487 + 0.04462 = 0.06197

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.06197 = 0.93803

So

P(X \geq 2) = 0.93803

5 0
2 years ago
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