Answer:
P( top two horses are predicted incorrectly in incorrect order)
= ![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
Step-by-step explanation:
In the horse race the outcome can be predicted in 5! = 120 ways.
Now suppose the top two horses were predicted incorrectly in incorrect order. Now, the top horse can be predicted incorrectly in 4 ways.
Suppose the top horse was predicted to be in k-th position where k = 2, 3 ,4,5
so the second horse can be predicted to be in place from 1 to (k - 1)
So, the top two horses can be predicted incorrectly in incorrect order
in
= 10 ways
and for each prediction of the two the remaining horses may be predicted in 3! = 6 ways.
Hence ,
P( top two horses are predicted incorrectly in incorrect order)
= ![\frac{6 \times 10}{120}](https://tex.z-dn.net/?f=%5Cfrac%7B6%20%5Ctimes%2010%7D%7B120%7D)
=![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
<span>
The good answer is 9
(9:9=1 and 27:9=3)</span>
3/6 possible out comes for heads and tails
Answer:
3 and 6
4 and 5
Step-by-step explanation:
Alternate interior angles are on the opposite sides of the transversal, t, and between the parallel lines, r and s
3 and 6 are alternate interior angles
4 and 5 are alternate interior angles
Answer:
I inserted your equation into desmos calculator
, Hope this helps :)
Have a great day!!