Log x √x + log √c c² = ?
1 answer:
Given that
log √x (x) + log c² (c)
⇛ log x^1/2 (x) + log c² (c)
We know that
log a^m (b^n) = m/n log a (b)
⇛ 1/2 log x (x) + 2 log c (c)
We know that
log a ( a) = 1
⇛ (1/2)(1) + 2(1)
⇛ (1/2)+2
⇛ (1+4)/2
⇛ 5/2
<u>Answer</u>:- log √x (x) + log c² (c) = 5/2
[(x) ,(c) , (a) represents the bases ]
<em>Additional</em><em> comment</em><em>:</em>
- (a+b)(a-b) = a²-b²
- log a^m (b^n) = m/n log a (b)
- log a ( a) = 1
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simplify the following expression. log(x2) - log(x) A. log(x^2+x) B. log(x^3) C. log(x^2-x) D. log(x)....
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Answer:
a² + b² = c · (e + d) = c × c = c²
a² + b² = c²
Please see attachment
Step-by-step explanation:
Statement, Reason
ΔADC ~ ΔACB, Given
AC/AD = BA/AC, The ratio of corresponding sides of similar triangles
b/e = c/b
b² = c·e
ΔBDC ~ ΔBCA, Given
BC/BA = BD/BC, The ratio of corresponding sides of similar triangles
a/c = d/a
a² = c·d
a² + b² = c·e + c·d
a² + b² = c · (e + d)
e + d = c, Addition of segment
a² + b² = c × c = c²
Therefore, a² + b² = c²
