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3 years ago

The Maxwell family goes out for dinner. The price for the

Mathematics

2 answers:

MAXImum [283]3 years ago

5 0

Answer:

$113.90

Step-by-step explanation:

Find the cost of the meal with sales tax:

90 x 0.075 = 6.525

Add that to the original cost of the meal:

90 + 6.525 = 96.525

Find the cost of the tip:

96.525 x 0.18 = 17.3745

Add the tip to the meal price:

96.525 + 17.3745 = 113.8995

Round to get your final answer

ipn [44]3 years ago

3 0

113.90 with exact change

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In 1999. Sara and her brother Xzavier got money when their rich uncle died. They

Hunter-Best [27]

Answer:

$406,300

Step-by-step explanation:

$2,700 + $3,600 = $6,300

$400,000 + $6,300 = $406,300

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3 years ago

Evaluate the expression when b=-7 and y=7 b-4y

Bess [88]

$b = - 7 \: y = 7$

$b - 4y$

$( - 7) - 4(7)$

$- 7 - 28$

$= - 35$

3 0

2 years ago

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kobusy [5.1K]

Answer:

it'll be the first one. in the sentence it says that Adult is MORE

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2 years ago

Find y so (-2, y) is a solution to 3x+5y=8

Yuri [45]

Answer:

y=14/5 or 2.8

Step-by-step explanation:

3(-2)+5y=8

-6+5y=8

+6 +6

5y=14

/5y /5y

y=14/5

4 0

2 years ago

Q3: Identify the graph of the equation and write and equation of the translated or rotated graph in general form. (Picture Provi

natta225 [31]

Answer:

b. circle; $2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0$

Step-by-step explanation:

The given conic has equation;

$x^2-5x+y^2=3$

We complete the square to obtain;

$(x-\frac{5}{2})^2+(y-0)^2=\frac{37}{4}$

This is a circle with center;

$(\frac{5}{2},0)$

This implies that;

$x=\frac{5}{2},y=0$

When the circle is rotated through an angle of $\theta=\frac{\pi}{3}$ ,

The new center is obtained using;

$x'=x\cos(\theta)+y\sin(\theta)$ and $y'=-x\sin(\theta)+y\cos(\theta)$

We plug in the given angle with x and y values to get;

$x'=(\frac{5}{2})\cos(\frac{\pi}{3})+(0)\sin(\frac{\pi}{3})$ and $y'=--(\frac{5}{2})\sin(\frac{\pi}{3})+(0)\cos(\frac{\pi}{3})$

This gives us;

$x'=\frac{5}{4} ,y'=\frac{5\sqrt{3} }{4}$

The equation of the rotated circle is;

$(x'-\frac{5}{4})^2+(y'-\frac{5\sqrt{3} }{4})^2=\frac{37}{4}$

Expand;

$(x')^2+(y')^2-\frac{5\sqrt{3} }{2}y'-\frac{5}{2}x'+\frac{25}{4} =\frac{37}{4}$

Multiply through by 4; to get

$4(x')^2+4(y')^2-10\sqrt{3}y'-10x'+25 =37$

Write in general form;

$4(x')^2+4(y')^2-10x'-10\sqrt{3}y'-12 =0$

Divide through by 2.

$2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0$

8 0

3 years ago