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wel
3 years ago
5

A circle is centered at K(0,0)K(0,0)K, left parenthesis, 0, comma, 0, right parenthesis. The point U(6,-4)U(6,−4)U, left parenth

esis, 6, comma, minus, 4, right parenthesis is on the circle.
Where does the point V(\sqrt{2},-7)V(
2
​
,−7)V, left parenthesis, square root of, 2, end square root, comma, minus, 7, right parenthesis lie?
Mathematics
2 answers:
Lapatulllka [165]3 years ago
6 0

Answer:

inside the circle

Step-by-step explanation:

Khan Academy

Ivenika [448]3 years ago
4 0

Answer: Inside the circle

Step-by-step explanation: Khan Academy

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Which represents the solution(s) of the graphed system of equations, y = x2 – 2x and y = –2x – 1? (1, –1) (0, 0) and (0, –1) (0,
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ANSWER

No solution

EXPLANATION

The first equation is

y =  {x}^{2}  - 2x

and the second equation is

y =  - 2x  - 1

We equate the two equations to obtain;

{x}^{2}  - 2x =  - 2x - 1

This implies that

{x}^{2}  =  - 2x + 2x - 1

{x}^{2}  =  - 1

There is no real number whose square is -1.

Therefore, the equation has no solution.

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Find the dy/dx for the equation below using implicit differentiation.
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First of all, recall that y is a product of function of x. We have three factors:

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The derivative of a product of function is computed by deriving one function at the time, and then adding all the results:

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Now plug f, f', g, g', h, h' in the formula above as required:

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