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tino4ka555 [31]
3 years ago
11

ou use productivity apps on your iPad tablet device while traveling between client sites. You're concerned that you may lose you

r iPad while on the road and want to protect the data stored on it from being compromised. Currently, your iPad uses a 4-digit PIN number for a passcode. You want to use a more complex alpha-numeric passcode. You also want all data on the device to be erased if the wrong passcode is entered more than 10 consecutive times. What should you do
Computers and Technology
1 answer:
SSSSS [86.1K]3 years ago
7 0

Answer:

  • <u>Enable the Erase data option</u>
  • <u>Disable the simple passcode option</u>

Explanation:

Most smartphone security experts agree that one way to prevent unauthorized access to one's iPad is to enable the erase data feature. Enabling this feature is believed to allow the possibility of all data on the device to be erased if a wrong passcode is entered after a specified number of times.

Of course, it is also possible to set a complex alphanumeric passcode, however, you'll need to first disable the simple passcode option.

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Name one app that currently has a positive impact on society and explain why you think it has had a positive effect.
VARVARA [1.3K]

Answer:

Wikipedia

Explanation:

Most people go to other websites because they don't like to read the articles, they just want the information now, but Wikipedia has some of the most detailed articles on information to do with anything, and it's free to use.

5 0
3 years ago
Describe the process of sorting the following list using the above algorithm:
Sindrei [870]

Answer:

A jewellery shop is having a sale.

A bracelet is reduced to £240.

a) What is the original price?

adadsadsadasdadad

5 0
3 years ago
Programming challenge description: Given a string comprising just of the characters (,),{,},[,] determine if it is well-formed o
nadezda [96]

Answer:

Employing Java language,

Explanation:

//for using stack data structure

import java.util.Stack;

//class definition

public class BracketMatch {

   //function to find the string is well formed or not

   public static boolean isWellFormed(String str) {

       //variable to store the character value

       char ch;

       //check if the first character itself is the end of the brackets

       if (str.charAt(0) == ')'||str.charAt(0) =='}'||str.charAt(0) ==']')

           return false;

       //creating a stack of character type

       Stack<Character> stack = new Stack<Character>();

       //iterating through the characters in string

       for(int i=0; i < str.length(); i++) {

           //storing the current character from the string in the variable

           ch = str.charAt(i);

           if(ch == '('||ch=='{'||ch=='[')

               //if the character is starting of the brackets push it into stack

               stack.push(ch);

           else if(ch == ')')

               //if it is closing bracket and the stack is empty then the string is not well formatted

               if(stack.empty())

                   return false;

               else if(stack.peek() == '(')

                   stack.pop();

               else

                   return false;

           else if(ch == '}')

               if(stack.empty())

                   return false;

               else if(stack.peek() == '{')

                   stack.pop();

               else

                   return false;

       }

       //returning the stack content, if the string will be well formed the stack would be empty

       //after all the operations

       return stack.empty();

   }

   //main method

   public static void main(String[] args) {

       //calling function to find if the string is welll formatted or not

       System.out.println(isWellFormed("{}"));

       //calling function to find if the string is welll formatted or not

       System.out.println(isWellFormed("([)]"));

   }

}

5 0
4 years ago
4. In this problem, we consider sending real-time voice from Host A to Host B over a packet-switchednetwork (VoIP). Host A conve
mina [271]

Answer:

The time elapsed is 0.017224 s

Solution:

As per the question:

Analog signal to digital bit stream conversion by Host A =64 kbps

Byte packets obtained by Host A = 56 bytes

Rate of transmission = 2 Mbps

Propagation delay = 10 ms = 0.01 s

Now,

Considering the packets' first bit, as its transmission is only after the generation of all the bits in the packet.

Time taken to generate and convert all the bits into digital signal is given by;

t = \frac{Total\ No.\ of\ packets}{A/D\ bit\ stream\ conversion}

t = \frac{56\times 8}{64\times 10^{3}}          (Since, 1 byte = 8 bits)

t = 7 ms = 0.007 s

Time Required for transmission of the packet, t':

t' = \frac{Total\ No.\ of\ packets}{Transmission\ rate}

t' = \frac{56\times 8}{2\times 10^{6}} = 2.24\times 10^{- 4} s

Now, the time elapse between the bit creation and its decoding is given by:

t + t'  + propagation delay= 0.007 + 2.24\times 10^{- 4} s + 0.01= 0.017224 s

8 0
3 years ago
5. What is a domain name used for?​
Mnenie [13.5K]

<u>Answer:</u>

Domain names serve to identify Internet resources, such as computers, networks, and services, with a text-based label that is easier to memorize than the numerical addresses used in the Internet protocols. A domain name may represent entire collections of such resources or individual instances.

<u />

<u>Explanation:</u>

*Hope this helps*

7 0
3 years ago
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