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julsineya [31]
2 years ago
7

Solve: 3(x - 2) = 12

Mathematics
2 answers:
Alecsey [184]2 years ago
7 0

Answer:

x=6

Step-by-step explanation:

3(x-2)=12

divide both sides by 3

x-2=4

add 2 to both sides

x-2+2=4+2

combine like terms

x=6

katrin [286]2 years ago
6 0

Answer:

x = 6

Step-by-step explanation:

So the equation looks like this:

3(x - 2) = 12

So the first thing we are going to do in this equation is multiply 3 by x and -2 in order to get rid of the parenthesis:

3(x - 2) = 12

(3 * x) + (3 * (-2)) = 12

3x - 6 = 12

Now we are going to add 6 to -6 and what you to one side of the equation you do to the other:

3x - 6 = 12

    + 6  + 6

3x = 18

Now in order to segregate the variable x from 3 we are going to have to divide 3x by 3 and what you do to one side of the equation you do to the other:

3x/3 = 18/3

x = 6

Now in order to check our work we are going to replace the variable x with six in the equation:

3(x - 2) = 12 = 3((6) - 2) = 12

(3 * 6) + (-2 * 3) = 12

18 - 6 = 12

12 = 12

Tada, hope this helps you!!

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Sarah would like to make a 6 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of a mixture that is 80%
weeeeeb [17]

Answer: a. The system that models this situation is,

x + y = 6 , 8 x + 5 y = 36.

b. Solution is x = 2lb and y = 4lb

where x is the quantity of 80% of peanuts mixture mix with y quantity of 50% of peanuts mixture for making 60% of peanuts mixture.

Step-by-step explanation:

Let x quantity of 80% of peanuts mixture mix with y quantity of 50% of peanuts mixture for making 60% of peanuts mixture.

Then According to the question,

x + y = 6      --------- (1)

And, 80 % of x + 50 % of y = 60 % of 6

⇒ 0.8 x + 0.5 y = 3.6

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Where equation 1) and equation 2) are the required equation which models the given situation.

Now, 8 × equation 1)

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equation (3) - equation (2)

we get, 3 y = 12

⇒ y = 4

By putting the value of y in equation (2)

we get, x = 2

Thus, he mixed 2 lb of mixture 80/20  and 4 lb of mixture 50/50 for making 6 lb of 50/50 mixture.


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