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Akimi4 [234]
3 years ago
15

Jeremy is shown the graph below and asked to write an equivalent equation. Jeremy writes the equation y=1+1/2x why is Jeremy's e

quation incorrect? what is the correct equation? a) the slope of the graph is 2; the equation should be y=1+2x b) the y-intercept of the graph is 0; the equation should be y=1/2x c) the slope of the graph is negative; the equation should be y=1-1/2x d) the y-intercept of the graph is 1/2 and the slope is 1; the equation should be y=1/2+x.
help please also I wasn't able to get the graph on here.
Thank you in advance!!
Mathematics
1 answer:
Contact [7]3 years ago
8 0

Answer:

The answer would be B.

Step-by-step explanation:

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soldier1979 [14.2K]

<u>Corrected Question</u>

Is the function given by:

f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right ​

continuous at x=4​? Why or why​ not? Choose the correct answer below.

Answer:

(D) ​Yes, f(x) is continuous at x = 4 because Lim_{x \to 4}f(x)=f(4)

Step-by-step explanation:

Given the function:

f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right

A function to be continuous  at some value c in its domain if the following condition holds:

  • f(c) exists and is defined.
  • Lim_{x \to c}$ f(x) exists.
  • f(c)=Lim_{x \to c}$ f(x)

At x=4

  • f(4)=\dfrac{1}{4}*4+1=2
  • Lim_{x \to 4}f(x)=2

Therefore: Lim_{x \to 4}f(x)=f(4)=2

By the above, the function satisfies the condition for continuity.

The correct option is D.

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