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SSSSS [86.1K]
4 years ago
10

You have been provided with the following logic

Mathematics
1 answer:
amid [387]4 years ago
5 0

If X and Y are Boolean variables, then X + Y represents disjunction (OR) and XY represents conjunction (AND), and X' denotes the negation (NOT). So X + Y = 1 if either X = 1 or Y = 1, and XY = 1 only if both X = 1 or Y = 1.

Now,

(X + Y) (X + Y') = XX + YX + XY' + YY'

… = X + X (Y + Y') + 0

… = X + X

… = X

or in table form,

\begin{array}{c|cccc}X&1&1&0&0\\Y&1&0&1&0\\Y'&0&1&0&1\\X+Y&1&1&1&0\\X+Y'&1&1&0&1\\(X+Y)(X+Y')&1&1&0&0\end{array}

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3 years ago
-2(2x-6)=8-(-5+3x) <br> how do you solve this ?
Serggg [28]

Answer:

x = -1

Step-by-step explanation:

first you "remove the parentheses" by multiplying the number on the outside of them to everything on the inside. for instance, -2 x 2x = -4x and -2 x -6 = 12 (because whenever you multiply two negatives, it turns into a positive) then, when there is a minus sign in front of parentheses,  you change the sign of everything within the parenthesis leaving you with a positive 5 and a negative 3x. so now you have a much simpler equation of -4x + 12 = 8 +5 -3x

next you want to of course add the 5 and the 8 to make it even more simple which would leave you with the equation:

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The next thing you need to do is get the unknown variable on one side of the equation. So you do add 4x do get the x on the right side which would leave you with 12 = 13 - 3x + 4x

So now you can do the same thing to the 13 to try to get it on the left by subtracting 13 from both sides

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now you make the equation simple by "combining the like terms" (which is something you'll hear a lot in algebra class)

making you equation -1 = 1x

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6 0
4 years ago
If approximately 8% of people are left-handed and two people are selected at random what is the probability that both people are
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8 0
3 years ago
Please Answer! I have been working on this for an hour and can't get it!
Ronch [10]
The answer is B = (-1, -5)

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rise/run
So we would apply 2 - 7
Which would be - 5

Give me brainliest if this helped
7 0
3 years ago
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