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____ [38]
3 years ago
8

What is the solution of the system of linear equations below?

Mathematics
1 answer:
harkovskaia [24]3 years ago
8 0

Answer:C.no solution

Step-by-step explanation:

100% correct. ツ

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the water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day.
marin [14]

To determine the average water use, 109 people must be sampled.

1.9 gallons is the standard deviation.

E = 0.15 gallons maximum error

1.9 gallons on average

90% is the critical value.

1.645 is the 90% confidence interval.

sample size requirement,

n = (((z ÷ 2) × σ) ÷ E)²

n = (((1.645 ÷ 2) × 1.9) ÷ 0.15)²

n = ((0.8225 × 1.9) ÷ 0.15)²

n = (1.5627 ÷ 0.15)²

n = (10.418)²

n = 108.53 ≈ 109

As a result, the minimal sample size necessary to determine the mean water use = 109.

It is determined by dividing the average standard error by the squared of the sample size, and it decreases with increasing sample size. In other words, when the sample size is sufficiently big, the population mean approaches the population mean.

To learn more about the sample interval at

brainly.com/question/13664567?referrer=searchResults

#SPJ4

8 0
1 year ago
Question 1 (1 point)
Brrunno [24]

Answer:

37°

Step-by-step explanation:

Subtract angle IJL from angle IJK.

6 0
2 years ago
Which ordered pair is a solution of the equation 2x − y = 9 (-4,1)
belka [17]
In order to confirm if which ordered pair is a solution of the given equation above, we can just simply plug in the values.
So based on my solution, the correct answer would be the third option: <span>(5,1) 
So let us try to plug in the values.
2(5) - 1 = 9
10 -1 = 9
9 = 9
So this is the correct one. Hope this answers your question.</span>
5 0
3 years ago
Algebra:
ladessa [460]
P+4+p-2+p = 47
3p + 2 = 47
p = 15
Answer: Priya is 15, Amirah is 19, and Shirley is 13
3 0
3 years ago
First I will build the envelope. For this, I am using a rectangular piece of material 28m long and 12m wide. Out of this materia
RUDIKE [14]

Answer:

3.728 cm²

90

Step-by-step explanation:

To built the envelope I am using a rectangular piece of material 28 m long and 12 m wide.  

Out of this material, I have to cut patches that are 1/12 the length and 2/15 the width of the whole material.

So, the length of the patches is 28 \times \frac{1}{12} = 2.33 m and the width of the patches is 12 \times \frac{2}{15} = 1.6 m.

Therefore, the area of the patches is (1.6 × 2.33) = 3.728 m² each. (Answer)

Now, the area of the rectangular piece of material is (28 × 12) = 336 m²

Hence, \frac{336}{3.728} = 90.37 ≈ 90 such patches can be made out of the whole material. (Answer)

3 0
3 years ago
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