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muminat
2 years ago
12

What is the center and radius of the circle with the given equation?

D8" id="TexFormula1" title="x^2+y^2+2x+8y=8" alt="x^2+y^2+2x+8y=8" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Mamont248 [21]2 years ago
5 0

Answer:

(- 1, - 4 ) and r = 5

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

To obtain this form from the given equation use the method of completing the square.

Given

x² + y² + 2x + 8y = 8 ( rearrange by collecting x and y terms )

x² + 2x + y² + 8y = 8

To complete the square

add ( half the coefficients of the x/ y terms )² to both sides

x² + 2(1)x + 1 + y² + 2(4)x + 16 = 8 + 1 + 16

(x + 1)² + (y + 4)² = 25 ← in standard form

with centre (h, k ) = (- 1, - 4 ) and r = \sqrt{25} = 5

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8 0
3 years ago
2x+y=-2
Over [174]

A

given the 2 equations

2x + y = - 2 → (1)

x + y = 5 → (2)

subtract (2) from (1) term by term to eliminate y

(2x - x ) + (y - y ) = (- 2 - 5 )

x + 0 = - 7 ⇒ x = - 7

substitute x = - 7 in either of the 2 equations and solve for y

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y = 5 + 7 = 12 → A


8 0
3 years ago
What is the intermediate step in the form (x+a)2 = b as a result of completing the square for the following
skelet666 [1.2K]

For this case we have the following expression:

x ^ 2-4x + 10 = 4x + 10

We follow the steps below:

We subtract 4x on both sides of the equation:

x ^ 2-4x + 10-4x = 4x + 10-4x\\x ^ 2-8x + 10 = 10

We subtract 10 from both sides of the equation:

x ^ 2-8x + 10-10 = 10-10\\x ^ 2-8x = 0

Now, we must complete squares.

When we have an equation of the form:

ax ^ 2 + bx + c = 0, if we want to complete squares we must subtract c on both sides of the equation obtaining:

ax ^ 2 + bx + c-c = -c\\ax ^ 2 + bx = -c

The square is completed by adding to both sides of the equation: (\frac{b}{2})^{2}

So, we have left:

ax^2+bx + (\frac {b} {2})^{2} = - c + (\frac {b} {2}) ^ {2}

In the given expression we have:

a = 1\\b = -8\\c = 0

And to complete the square we have:

(\frac {b} {2}) ^ {2} = (\frac {-8} {2}) ^ {2} = 16

Rewriting we have:

x ^ 2-8x + 16 = 16

We factor the left side of the equation, that is, we look for two numbers that when added together result in -8 and when multiplied as a result 16. We have:

-4-4 = -8\\-4 * -4 = 16

So, we have:

(x-4) (x-4) = 16\\(x-4) ^ 2 = 16

Answer:

The intermediate step is to complete squares

(x-4) ^ 2 = 16


7 0
3 years ago
Can someone please help
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Answer:  5y^3-7x^5

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