Question

The equation of the graphed line in point-slope form is _______, and its equation in slope-intercept form is .

Answer 1

Answer:

Point-slope form equation line

$(y-3)=(-0.6)\times (x+2)$

Slope-intercept form is:

$y=-0.6x+1.8$

Step-by-step explanation:

Point-slope form equation line passing through points $(x_1,y_1)(x_2,y_2)$

Slope = m  =$\frac{y-2-y_1}{x_2-x_1}$

slope-intercept form is:

y = mx +c

where : c = intercept of on axis

$(y-y_1)=m\times (x-x_1)$

Equation of line passing through (-2,3) and (3,0).

$m=\frac{0-3}{3-(-2)}=-0.6$

$(y-3)=-0.6\times (x-(-2))$

Point-slope form equation line

$(y-3)=(-0.6)\times (x+2)$

For slope-intercept form open the brackets of Point-slope form equation l:

$y-3=-0.6x-1.2$

So, the slope-intercept form is:

$y=-0.6x+1.8$