All categories

3 years ago

Determine the basic probability.

Mathematics

1 answer:

shtirl [24]3 years ago

3 0

Green would be 20% and red would be 50%

You might be interested in

BRAINLIEST <br> Please answer these

zheka24 [161]

3.14 is used for pi.

6. r = $\sqrt{\frac{A}{\pi } }$

14.00

7. d = $\frac{c}{\pi }$

5.00

8. d = $2 \sqrt{\frac{A}{\pi } }$

23.01

9. r = $\frac{c}{2\pi }$

20.01

10. d $\pi$ = $2 \sqrt{{A}$

31 $\pi$

11. r $\pi$ = $\frac{c}{2}$

22.5 $\pi$

Hope this helps :)

6 0

3 years ago

List the elements of the set of all letters in the word "FOUR"

aleksley [76]

Answer:

{F, O, U, R} in the word 'FOUR'

3 0

3 years ago

Let us have four distinct collinear points $a,$ $b,$ $c,$ and $d$ on the cartesian plane. the point $c$ is such that $\dfrac{ab}

Deffense [45]

Start with a line segment connecting two points, A and B. $\dfrac{DA}{BA}=3$ means DA is 3 times longer than BA. Clearly, D cannot fall between A and B because that would mean DA is shorter than BA. So there are two possible locations where D can be placed on the line relative to A and B.

But with $\dfrac{DB}{BA}=2$ , or the fact that DB is 2 times longer than BA, we can rule out one of these positions; referring to the attachment, if we place D to the left of A, then DB would be 4 times longer than BA.

Finally, $\dfrac{AB}{CB}=\dfrac12$ , so that CB is 2 times longer than AB. Again we have two possible locations for point C (it cannot fall between A and B), but one of them forces C to occupy the same point as D. However, A, B, C, D are distinct, so C must fall to the left of A.

Now let $d$ be the length of AB. Then the length of CD in terms of $d$ is $4d$ . We have the coordinates of C and D, and the distance between them is $\sqrt{(4-0)^2+(0-4)^2}=4\sqrt2$ . So

$4d=4\sqrt2\implies d=\sqrt2$

The slope of the line through C and D is

$\dfrac{0-4}{4-0}=-1$

and so the equation of the line through these points is

$y-4=-(x-0)\implies x+y=4$

So the coordinates of A are $(x,y)=(x,4-x)$ . The distance between C and A is $d=\sqrt2$ , so we have

$\sqrt{(x-0)^2+(4-x-4)^2}=\sqrt{2x^2}=|x|\sqrt2=\sqrt2\implies|x|=1$

Since A falls to the right of C (in the $x,y$ plane, not just in the sketch), we know to take the positive value $x=1$ . Then the $y$ coordinate is $y=4-1=3$ .