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Semenov [28]
2 years ago
13

Arrange the cards into three pairs of the same total. -7,-5,-3,3,1,-1

Mathematics
1 answer:
ale4655 [162]2 years ago
3 0

the answer is ( -7; 3) (-5; 1) ( -3;-1)

ok done. Thank to me :>

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A sweater is on sale for 30% off the ticketed price of $84. How much will the sweater cost after the discount?
Marianna [84]
84 x .70 = $58.80

Or if you want to do it the long way you can calculate the actual discount (your savings from this purchase first then subtract it from the original price of $84. It`s just easier to figure out what is left (which is 70% of $84).
3 0
3 years ago
Can anyone help me out on this
swat32

Answer: y = 1/8x+1

y=mx+b is slope intercept form

given m = 1/8 and a point we can find b by plugging in what we have

1=1/8(8)+b

1=1b

b=1

So then we know m = 1/8 and b = 1

y=1/8x+1 is the answer

3 0
2 years ago
Pls help I’ll give the big brain award or whatever
andre [41]

Answer:

2

1

-0

-1

-2

1

Step-by-step explanation:

300x80=24,000

7 0
3 years ago
This is a continuous set of points in the coordinate plane. It can be, but is not always, straight.
castortr0y [4]

Answer:

Linear. While all linear equations produce straight lines when graphed, not all linear equations produce linear functions. In order to be a linear function, a graph must be both linear (a straight line) and a function (matching each x-value to only one y-value).

5 0
3 years ago
Some transportation experts claim that it is the variability of speeds, rather than the level of speeds, that is a critical fact
scZoUnD [109]

Answer:

Explained below.

Step-by-step explanation:

The claim made by an expert is that driving conditions are dangerous if the variance of speeds exceeds 75 (mph)².

(1)

The hypothesis for both the test can be defined as:

<em>H</em>₀: The variance of speeds does not exceeds 75 (mph)², i.e. <em>σ</em>² ≤ 75.

<em>Hₐ</em>: The variance of speeds exceeds 75 (mph)², i.e. <em>σ</em>² > 75.

(2)

A Chi-square test will be used to perform the test.

The significance level of the test is, <em>α</em> = 0.05.

The degrees of freedom of the test is,

df = n - 1 = 55 - 1 = 54

Compute the critical value as follows:

\chi^{2}_{\alpha, (n-1)}=\chi^{2}_{0.05, 54}=72.153

Decision rule:

If the test statistic value is more than the critical value then the null hypothesis will be rejected and vice-versa.

(3)

Compute the test statistic as follows:

\chi^{2}=\frac{(n-1)\times s^{2}}{\sigma^{2}}

    =\frac{(55-1)\times 94.7}{75}\\\\=68.184

The test statistic value is, 68.184.

Decision:

cal.\chi^{2}=68.184

The null hypothesis will not be rejected at 5% level of significance.

Conclusion:

The variance of speeds does not exceeds 75 (mph)². Thus, concluding that driving conditions are not dangerous on this highway.

7 0
3 years ago
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