Answer:
0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Mean of 0.6 times a day
7 day week, so 
What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

In which




So

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.
Answer:
Step-by-step explanation:
a)
- 1.5x² + 6x + * =
- 1.5(x² + 4x + *) =
- 1.5(x² + 2*2x + 4) =
- 1.5(x + 2)²
- * = 1.5*2² = 6
b)
- 2x² - 5x + * =
- 2(x² - 2.5x + *) =
- 2(x² - 2*1.25x + 1.25²)=
- 2(x - 1.25)²
- * = 2*(1.25)² = 3.125 or 25/8
The answer is equivalent to 10*9*8 as their is one less student to go after each presentation.
720 ways.

notice, it was pawned for only 1 month, so the "yearly" rate is for 1 month, which is 1/12 of the year, since a year has 12 moths
you'll get a rate in decimal terms, to get the % amount, just multiply it times 100
Answer:
csdkc kwhbfc d cjasd c
Step-by-step explanation:
sdjnf ewaihfbashehkf liq4bf;wjhf