Question

Factor xy−4y+4x−16 by grouping

Answer 1

Answer:

$(y+4)(x-4)$

Step-by-step explanation:

Given the expression:

$xy-4y+4x-16$

$(xy-4y)+(4x-16)$

Take the common factor

$y(x-4)+4(x-4)$

$(y+4)(x-4)$

Answer 2

Answer:

(x-4)(y+4)

Step-by-step explanation:

First you group the expression to get (xy+4x)+(-4y-16)

then factor to get x(y+4)-4(y+4)

and factor again to get (x-4)(y+4)