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Setler [38]
2 years ago
15

in a park of 30 people, 15 were walking, 7 were playing and 6 were just running. find the percentage of people who were not doin

g any activity
Mathematics
2 answers:
iris [78.8K]2 years ago
8 0

Answer: 7%

Step-by-step explanation:

15 + 7 + 6 = 28

Fraction of no activity is 2/30

divide 2/30

0.06666667

Round up

0.07 = 7%

monitta2 years ago
7 0

Answer:

6.67

Step-by-step explanation:

Because in the park there are 30 people OK

15 were walking

7 were playing

6 were running.

15 + 7 + 6=28

Meaning there are still 2 people left so that is 6.67 =% of the people.

Hope it helps have a great afternoon:)

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7/10

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answer:

m/s --- km/h = \frac{1000}{3600}

km/h= \frac{5}{18}

6m/s= \frac{6*5}{18}

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6 0
2 years ago
345678.757 *(times) 74529.4675<br> Whoever answers it right is the BRAINLIEST!
Kisachek [45]

Answer:

25763253685.3

Step-by-step explanation:

5 0
3 years ago
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A.It will stay the same
DanielleElmas [232]

Answer:

B

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Let's arrange the data set in increasing order.

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4 0
3 years ago
Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity. In the given triangle ABC, angle A
lana66690 [7]

The relationship between the lengths of the sides of a right triangle are

given by Pythagoras theorem.

  • Part A: <u>ΔABC is similar to ΔADC</u>
  • Part B: ΔABC and ΔADC are similar according <u>AA similarity postulate</u>
  • Part C: <u>DA = 6</u>

Reasons:

Part A:

∠A = 90°

Segment AD ⊥ Segment BC

Location of point D = Side BC

Part A: In triangle ΔABC, we have;

∠A = 90°, ∠B = 90° - ∠C

In triangle ΔADC, we have;

∠ADC = 90°, ∠DAC = 90° - ∠C

∴ <u>ΔABC is similar to ΔADC</u> by Angle-Angle, AA, Similarity Postulate

Part B: The triangles are similar according to <u>AA similarity postulate</u>,

because two angles in one triangle are equal to two angles in the other

triangle and therefore, by subtraction property of equality, the third angle

in both triangles are also equal.

Part C: The length of DB = 9

The length of DC = 4

Required: Length of segment DA

In triangle ΔABD, we have;

∠BDA = 90°= ∠ADC

∠DAC ≅ ∠B by Congruent Parts of Congruent Triangles are Congruent

Therefore;

ΔABD ~ ΔADC by AA similarity, which gives;

\displaystyle \frac{\overline{DA}}{\overline{DC}}  = \frac{\overline{BD}}{\overline{DA}}

\overline{DA}^2 = \overline{DC} \times \overline{BD}

Which gives;

\overline{DA}^2 = 4 × 9 = 36

\overline{DA} = √(36) = 6

\overline{DA}<u> = 6</u>

Learn more here:

brainly.com/question/2269451

3 0
2 years ago
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