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olga2289 [7]
3 years ago
13

Identify the type of regression that returns the equation y = x^2 + 7x - 15.

Mathematics
1 answer:
horrorfan [7]3 years ago
4 0

Answer:

  B.  quadratic

Step-by-step explanation:

The equation y=x^2+7x-15 is a quadratic equation. It might be the result of a quadratic regression.

_____

The descriptors "linear," "quadratic," "exponential," and "power" describe the sort of equation that is used to try to match the data. Quadratic regression returns a quadratic equation.

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Area = 6.25\pi ft^2

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6 0
2 years ago
Match each of the trigonometric expressions below with the equivalent non-trigonometric function from the following list. Enter
Levart [38]

Answer:

Match each of the trigonometric expressions below with theequivalent non-trigonometric function from the following list.Enter the appropiate letter(A,B, C, D or E)in each blank

A . tan(arcsin(x/8))

B . cos (arsin (x/8))

C. (1/2)sin (2arcsin (x/8))

D . sin ( arctan (x/8))

E. cos (arctan (x/8))

These are the spaces to fill out :

.. ..........x/64 (sqrt(64-x^2))

.............x/sqrt(64+x^2)

.............sqrt(64-x^2)/8

..............x/sqrt(64-x^2)

..............8/sqrt(64+x^2)

A. ........tan(arcsin(x/8))  =......x/sqrt(64-x^2)

B .      cos (arsin (x/8))  ....sqrt(64-x^2)/8

Step-by-step explanation:

To solve this we have to find the missing sides to each of the triange discribed in prenthesis thus

A we have the sides of the triangle given by x, 8 and  \sqrt{8^{2} - x^{2} }or  \sqrt{64 - x^{2} }

thus tan(arcsin(x/8))  = \frac{x}{\sqrt{64 - x^{2} }}  =

Therefore  ........tan(arcsin(x/8))  =......x/sqrt(64-x^2)

B

Here we have cos = adjacent/hypotenuse where adjacent side is \sqrt{64 - x^{2} } and hypothenuse = 8 we have \sqrt{64 - x^{2} }/8

B .      cos (arsin (x/8))  ....sqrt(64-x^2)/8

4 0
3 years ago
Can someone help me?
Oxana [17]

Answer:

Step-by-step explanation:

To start calculating, we first need to make some proof.

Firstly, since AB = AC, we know that ΔABC is isosceles, which means that ∠ABC = ∠ACB.

Now, looking only to ΔBDE and ΔCDF, we can see that they are similar, because the two of its angles are congruent:

∠BED=∠CFD

∠DBE=∠DCF

To make it easier to visualize which are the corresponding vertexes, we can draw them like this:

And we need to remember that BC is 24, so:

BD+CD=24

Since the triangles are similar, their corresponding sides have constant ratio, which we can calculate from the corresponding sides DE and CF:

r=\frac{CF}{DE} =\frac{7.5}{4.5} =\frac{5}{3}

This ratio is the same for the other corresponding sides, so we can apply that for BD and CD:

r=\frac{CD}{BD} =\frac{5}{3}\\&#10; \frac{BD}{CD}=\frac{3}{5}  \\\\&#10;BD=\frac{3}{5} Cd

Thus, the measure of CF is approximately 13, alternative D.

3 0
3 years ago
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