Beneze recipe for granola bars close for 3 1/2 cups of oatmeal he only has 16 cup scoop how many scoops of oatmeal he need for t
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Answer:
<h2>h = 4 cm</h2><h2 />Step-by-step explanation:
V = π r² h
where r = 3 cm
V = 36π cm³
solve for h
plugin values into the formula:
36π = π 3² h
h = <u> 36π </u>
π 3²
h = 4 cm
Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S =
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer