As a rule of thumb, the sampling distribution of the sample proportion can be approximated by a normal probability distribution whenever the sample size is large.
<h3>What is the Central limit theorem?</h3>
- The Central limit theorem says that the normal probability distribution is used to approximate the sampling distribution of the sample proportions and sample means whenever the sample size is large.
- Approximation of the distribution occurs when the sample size is greater than or equal to 30 and n(1 - p) ≥ 5.
Thus, as a rule of thumb, the sampling distribution of the sample proportions can be approximated by a normal probability distribution when the sample size is large and each element is selected independently from the same population.
Learn more about the central limit theorem here:
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Answer:
The answer to your question is below.
Step-by-step explanation:
14.- Use proportions to solve these problems.
![\frac{x + 6}{10} = \frac{x + 9}{14}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%20%2B%206%7D%7B10%7D%20%3D%20%5Cfrac%7Bx%20%2B%209%7D%7B14%7D)
14(x + 6) = 10(x + 9)
14x + 84 = 10x + 90
14x - 10x = 90 - 84
4x = 6
x = 6/4
x = 3/2
15.- ![\frac{x - 1}{8} = \frac{x + 2}{10}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%20-%201%7D%7B8%7D%20%3D%20%5Cfrac%7Bx%20%2B%202%7D%7B10%7D)
10(x - 1) = 8(x + 2)
10x - 10 = 8x + 16
10x - 8x = 16 + 10
2x = 26
x = 26 / 2
x = 13
16.- ![\frac{x + 1}{9} = \frac{10/3}{5}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%20%2B%201%7D%7B9%7D%20%3D%20%5Cfrac%7B10%2F3%7D%7B5%7D)
5(x + 1) = 9(10/3)
5x + 5 = 30
5x = 30 - 5
5x = 25
x = 25 / 5
x = 5
Answer:
Take 8÷3.5. So the answer is aprominently 2.29.
Answer:
x=c/a-b/a
Step-by-step explanation:
ax+b=c
1) Subtract b from both sides:
ax=c-b
2) Divide both sides by a:
x=c/a-b/a