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Ira Lisetskai [31]

3 years ago

6

Aldo rented a truck for one day there was a base fee of $19.95 and there was an additional charge of 79cents for each mile drive

n aldo had to pay $234.04 when he returned the truck for how many miles did he drive the truck

1 answer:

tensa zangetsu [6.8K]3 years ago

8 0

Answer:

2.96

Step-by-step explanation:

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Addison is paid $40 for tutoring. She spends $16.83 on dinner. How much money does Addison have left and why?

dimaraw [331]

Answer:

23.17

Step-by-step explanation:

40 - 16.83 = 23.17

She has this amount because she spent it

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frutty [35]

Answer:

h = (S- 2πr²)/(2πr)

Step-by-step explanation:

<u>Given</u>

Formula S = 2πr² + 2πrh

<u>Solve for h</u>

S = 2πr² + 2πrh
2πrh = S - 2πr²
h = (S- 2πr²)/(2πr)

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3 years ago

for f(x)=(x-3)/(x^(2)-4), the function is at x=2 continuous discontinuous with an infinite discontinuity discontinuous with a ju

Igoryamba

Answer:

ITS UNDEFINED

Step-by-step explanation:

2-3)/2^2 - 4

-1/(4-4)

-1/0

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JulsSmile [24]

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Step-by-step explanation:

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3 years ago

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kumpel [21]

Answer:

The rational numbers are $\frac{11}{3}, 6.25, 0.01045,\sqrt{\frac{16}{81}},0.\bar{42}$ and the irrational functions are $\sqrt{48},\sqrt{\frac{3}{16}}$ .

Step-by-step explanation:

A rational number can be expressed in the form of $\frac{p}{q}$ , where p and q are integers and q is not equal to 0. For example $2,3.5,\frac{2}{5},...$ .

An irrational function can not be expressed in the form of $\frac{p}{q}$ , where p and q are integers and q is not equal to 0. For example $\sqrt{2},\sqrt{3},\sqrt{5},...$ .

If any number is multiplied by a irrational number then the resultant number is an irrational number.

By the above definition we can conclude that:

The number $\frac{11}{3}$ is a rational number.

$\sqrt{48}=\sqrt{16\times 3}=4\sqrt{3}$

Therefore $\sqrt{48}$ is an irrational number.

$6.25=\frac{625}{100}=\frac{25}{4}$

Therefore 6.25 is a rational number.

$0.01045=\frac{1045}{100000}=\frac{209}{20000}$

Therefore 0.01045 is a rational number.

$\sqrt{\frac{16}{81}}=\frac{4}{9}$

The number $\frac{16}{81}$ is a rational number.

$\sqrt{\frac{3}{16}}=\frac{\sqrt{3}}{4}$

The number $\frac{3}{14}$ is an irrational number.

$0.\bar{42}=\frac{42}{99}$

Therefore $0.\bar{42}$ is an irrational number. The numbers with recursive bar are always rational numbers.

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3 years ago