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3 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP FASTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT

Mathematics

2 answers:

finlep [7]3 years ago

5 0

Answer:

10 11/15

Step-by-step explanation:

Rewriting our equation with parts separated

=4+13+6+25

Solving the whole number parts

4+6=10

Solving the fraction parts

1/3 + 2/5 =

5/15+6/15=11/15

Combining the whole and fraction parts

10+11/15=10 11/15

pogonyaev3 years ago

4 0

Answer:

Step-by-step explanation:

-10 11/15

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In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second

Molodets [167]

Given:

In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second.

To find:

The equation for the given situation if the sum of the numbers is 77.

Solution:

a. Let the first number in the set is x.

The second is 3 more than the first. So, the second number is $(x+3)$ .

The 3rd number is a square of the second. So, the third number is $(x+3)^2$ .

Therefore, the first, second and third numbers are $x,(x+3),(x+3)^2$ respectively.

b. The sum of the numbers is 77.

First number + Second number + Third number = 77

c. So, the equation in terms of x is:

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Therefore, the required equation is $x+(x+3)+(x+3)^2=77$ .

d. On simplification, we get

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Subtract 77 from both sides.

$x^2+8x+12-77=77-77$

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Therefore, the simplified form of the required equation is $x^2+8x-65=0$ .

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Answer:

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3 years ago