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3 years ago

What is the area of the triangle

Mathematics

1 answer:

Stels [109]3 years ago

8 0

Answer:

ummmm

Step-by-step explanation:

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Find the definite integral from 0 to 1/16 of arcsin(8x)/sqrt(1-64x^2)dx

kolezko [41]

$\displaystyle\int_0^{1/16}\frac{\arcsin8x}{\sqrt{1-64x^2}}\,\mathrm dx$

First let $y=8x$ , so that $\mathrm dx=\dfrac{\mathrm dy}8$ to write the integral as

$\displaystyle\frac18\int_0^{1/2}\frac{\arcsin y}{\sqrt{1-y^2}}\,\mathrm dy$

Now recall that $(\arcsin y)'=\dfrac1{\sqrt{1-y^2}}$ , so substituting $z=\arcsin y$ should do the trick. The integral then becomes

$\displaystyle\frac18\int_0^{\pi/6}z\,\mathrm dz=\frac1{16}z^2\bigg|_{z=0}^{z=\pi/6}=\frac{\pi^2}{576}$

8 0

3 years ago

Find the midpoint of a and b when a has coordinates (-5,3) and b has coordinates (3,-1)

azamat

To find the x coordinate of the midpoint, add the x coordinates and divide by 2
(-5+3)/2 = -2/2 = -1
To find the y coordinate of the midpoint, add the y coordinates and divide by 2
(3+-1)/2 = 2/2 = 1
(-1,1)

6 0

3 years ago

Read 2 more answers

Connor wants to save up money to buy his math teacher a PS5 for the holidays. After 4 weeks, he has $178 saved up. After 9 weeks

Scorpion4ik [409]

Answer:

1.) Over these two moments he has saved up more money to buy a PS5 for his teacher

2.) $32 dollars per week

3.) $178

Step-by-step explanation:

2.) 338-178= 160/5= $32

3.)$178

7 0

3 years ago

Read 2 more answers

Which answer is correct? Please hurry <3

liq [111]

answer is 4

Es tut mir nicht so leid

6 0

3 years ago

Suppose there is a pile of quarters, dimes, and pennies with a total value of $1.06. How much of each coin can be present wit

SpyIntel [72]

Hello,

I note (a,b,c) the result of a quarters, b dimes and c pennies:

2 solutions:
106=( 3, 3, 1)=( 1, 8, 1)

106=( 0, 0, 106) but : 100= 0*25+ 0*10+ 100
106=( 0, 1, 96) but : 100= 0*25+ 1*10+ 90
106=( 0, 2, 86) but : 100= 0*25+ 2*10+ 80
106=( 0, 3, 76) but : 100= 0*25+ 3*10+ 70
106=( 0, 4, 66) but : 100= 0*25+ 4*10+ 60
106=( 0, 5, 56) but : 100= 0*25+ 5*10+ 50
106=( 0, 6, 46) but : 100= 0*25+ 6*10+ 40
106=( 0, 7, 36) but : 100= 0*25+ 7*10+ 30
106=( 0, 8, 26) but : 100= 0*25+ 8*10+ 20
106=( 0, 9, 16) but : 100= 0*25+ 9*10+ 10
106=( 0, 10, 6) but : 100= 0*25+ 10*10+ 0
106=( 1, 0, 81) but : 100= 1*25+ 0*10+ 75
106=( 1, 1, 71) but : 100= 1*25+ 1*10+ 65
106=( 1, 2, 61) but : 100= 1*25+ 2*10+ 55
106=( 1, 3, 51) but : 100= 1*25+ 3*10+ 45
106=( 1, 4, 41) but : 100= 1*25+ 4*10+ 35
106=( 1, 5, 31) but : 100= 1*25+ 5*10+ 25
106=( 1, 6, 21) but : 100= 1*25+ 6*10+ 15
106=( 1, 7, 11) but : 100= 1*25+ 7*10+ 5
106=( 1, 8, 1) is good
106=( 2, 0, 56) but : 100= 2*25+ 0*10+ 50
106=( 2, 1, 46) but : 100= 2*25+ 1*10+ 40
106=( 2, 2, 36) but : 100= 2*25+ 2*10+ 30
106=( 2, 3, 26) but : 100= 2*25+ 3*10+ 20
106=( 2, 4, 16) but : 100= 2*25+ 4*10+ 10
106=( 2, 5, 6) but : 100= 2*25+ 5*10+ 0
106=( 3, 0, 31) but : 100= 3*25+ 0*10+ 25
106=( 3, 1, 21) but : 100= 3*25+ 1*10+ 15
106=( 3, 2, 11) but : 100= 3*25+ 2*10+ 5
106=( 3, 3, 1) is good
106=( 4, 0, 6) but : 100= 4*25+ 0*10+ 0

5 0

3 years ago