Please answer! don’t forget to specify what to put for select

The mean weight of cherry tomatoes on a farm is about 57 grams. The farmer is interested in testing a new type of fertilizer. Th

Nookie1986 [14]

Answer:

The weight of a tomato depends on the variety of tomato. There are cherry, plum, grape, roma, and beef tomatoes of various sizes. The following tables shows different types of tomatoes, along with the average weight (in grams and ounces), the number of tomatoes per kilogram, and the number of tomatoes per pound.

Step-by-step explanation:

6 0

3 years ago

Suppose Department X is 8,000 square feet, Department Y is 5,000 square feet, and Department Z is 6,000 square feet. What's the

den301095 [7]

Answer:

31.6%

Step-by-step explanation:

it is given that

Area of Department X = 8,000 square feet

Area of Department Y = 5,000 square feet

Area of Department Z = 6,000 square feet

now the total area = $8000+5000+6000$

= $19,000$ square feet

Percentage of area covered by Department Z = $\frac{area of Department Z}{total area }100$ %

= $\frac{6000}{19000} 100$ %

= $31.6$ %

percentage of overhead expenses applied to Department Z = percentage of area covered by Department Z

hence we have,

percentage of overhead expenses applied to Department Z = 31.6%

4 0

3 years ago

Which statement about rational numbers is true?

iogann1982 [59]

Answer:

the true one is all fractions containing integers are rational numbers is true

Step-by-step explanation:

i think

5 0

3 years ago

Read 2 more answers

Please assist me with #5, 6, 7, 8

Leona [35]

Answer:

5a. -0.4 m/s²

5b. 290 m

6. 12.9 s

7. 100 s

8. 17.2 km/hr

Step-by-step explanation:

5. "While approaching a police officer parked in the median, you accelerate uniformly from 31 m/s to 27 m/s in a time of 10 s.

a. What is your acceleration?

b. How far do you travel in that time?"

Given:

v₀ = 31 m/s

v = 27 m/s

t = 10 s

Find: a and Δx

v = at + v₀

(27 m/s) = a (10 s) + (31 m/s)

a = -0.4 m/s²

Δx = ½ (v + v₀) t

Δx = ½ (27 m/s + 31 m/s) (10 s)

Δx = 290 m

6. "If a pronghorn antelope accelerates from rest in a straight line with a constant acceleration of 1.7 m/s², how long does it take for the antelope to reach a speed of 22 m/s?"

Given:

v₀ = 0 m/s

v = 22 m/s

a = 1.7 m/s²

Find: t

v = at + v₀

(22 m/s) = (1.7 m/s²) t + (0 m/s)

t = 12.9 s

7. "A 1200 kg airplane starts from rest and moves forward with a constant acceleration of 5 m/s² along a runway that is 250 m long. How long does it take the plane to travel the 250 m?"

Given:

v₀ = 0 m/s

a = 5 m/s²

Δx = 250 m

Find: t

Δx = v₀ t + ½ at²

(250 m) = (0 m/s) t + ½ (5 m/s²) t²

t = 100 s

8. "During a marathon, a runner runs the first 10 km in 0.58 hours, the next 10 km in 0.54 hours and the last 10 km in 0.62 hours. What is the average speed of the runner during that marathon?"

This isn't a constant acceleration problem, so there's no need for a chart.

Average speed = total distance / total time

v = (10 km + 10 km + 10 km) / (0.58 hr + 0.54 hr + 0.62 hr)

v = 30 km / 1.74 hr

v = 17.2 km/hr

3 0

3 years ago

Some research suggests that police officers are more likely to make an arrest in the presence of bystanders. If mentally disorde

zmey [24]

Answer:

$t=\frac{7.03-3.58}{\frac{9.42}{\sqrt{20}}}=1.638$

$p_v =P(t_{(19)}>1.638)=0.0589$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true mean is not significantly higher than 3.58 at 5% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=7.03$ represent the sample mean

$s=9.42$ represent the sample standard deviation

$n=20$ sample size

$\mu_o =3.58$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 3.58 :

Null hypothesis: $\mu \leq 3.58$

Alternative hypothesis: $\mu > 3.58$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{7.03-3.58}{\frac{9.42}{\sqrt{20}}}=1.638$

P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=20-1=19$

Since is a right tailed test the p value would be:

$p_v =P(t_{(19)}>1.638)=0.0589$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true mean is not significantly higher than 3.58 at 5% of signficance.

7 0

3 years ago