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3 years ago

Please answer! don’t forget to specify what to put for select

Mathematics

1 answer:

masha68 [24]3 years ago

5 0

Angle 11 is 119
and select alternate interior angles theorem

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Repost this for help

inna [77]

Answer:

I'm sorry I don't know if I do get an idea I'll come back and edit

Step-by-step explanation:

3 0

3 years ago

X+4/8 = 1/2

Nina [5.8K]

Answer:

x=0

Step-by-step explanation:

4/8=1/2, so:

x+1/2=1/2

x=0

5 0

3 years ago

Read 2 more answers

90x+26+X<br> What is the answer

liberstina [14]

Answer:

Step-by-step explanation:

Well you can make the put the x with 90x and that will make 91x. Then you can add 91x with 26. 91x+26= 13(7x + 2). Hope that helped

7 0

3 years ago

Read 2 more answers

Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz. An ornithologi

il63 [147K]

Answer:

The formula to generate 70% confidence interval is: $[\overline{x} - 0.013, \overline{x} + 0.013]$ , in which $\overline{x}$ is the sample mean.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.7}{2} = 0.15$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.15 = 0.85$ , so Z = 1.037.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz.

This means that $\sigma = 0.04$ .

Sample of 10 birds:

This means that $n = 10$ .

The margin of error is of:

$M = z\frac{\sigma}{\sqrt{n}}$

$M = 1.037\frac{0.04}{\sqrt{10}}$

$M = 0.013$

The lower end of the interval is the sample mean of $\overline{x}$ subtracted by M.

The upper end of the interval is the sample mean of $\overline{x}$ added to M.

Then, the formula to generate 70% confidence interval is: $[\overline{x} - 0.013, \overline{x} + 0.013]$ , in which $\overline{x}$ is the sample mean.

8 0

3 years ago

Help plz I don't understand at all

Levart [38]

What does it say 3.5 or 3.50

6 0

3 years ago