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3 years ago

Explain how to do distributive property. Use an example.

Mathematics

1 answer:

klasskru [66]3 years ago

3 0

Answer:

so we have 4(3x + 10)

then we are going to take the 4 and distribute it into our problem

so: 4(times)3x and then 4( times)10

to get :

Step-by-step explanation:

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If d is the midpoint of the segment AC

3241004551 [841]

Based on the statement below, if d is the midpoint of the segment AC, the length of the segment AB is 4.5cm.

<h3>What is the line segment about?</h3>

in the question given,

AC = 3cm,

Therefore, AD and DC will be = 1.5cm segments each.

We are given C as the midpoint of segment DB.

So CB = 1.5cm.

The representation of the line segment is:

A-----------D------------C-------------B

1.5 1.5 1.5

Since AD, DC and CB are each 1.5cm segments. Then the equation will be:

= 1.5 + 1.5 + 1.5

= 4.5

Therefore, The length of the segment AB is 4.5cm.

See full question below

If D is the midpoint of the segment AC and C is the midpoint of segment DB , what is the length of the segment AB , if AC = 3 cm.

Learn more about midpoint from

brainly.com/question/10100714

#SPJ1

3 0

2 years ago

Helpppppppp mathhhhhhhh

ddd [48]

That's like 20 degrees

3 0

3 years ago

Read 2 more answers

Geometry

Mademuasel [1]

DB is a median (given). It goes from vertex point D to midpoint B.

The point B is the midpoint of segment AC. So B cuts AC into two equal halves: AB and AC
Meaning AB = AC

AC = AB+BC ... segment addition postulate
AC = AB+AB ... substitution; replace BC with AB (valid because AB = AC)
AC = 2*AB
2*AB = AC
2*AB = 50 ... substitution; replace AC with 50
2*AB/2 = 50/2 ... divide both sides by 2
AB = 25 which is the answer

6 0

3 years ago

Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0

Debora [2.8K]

So, the definite integral $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Given that

$\int\limits^1_0 {x^{2} } \, dx = 13$

We find

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx$

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, $Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6\int\limits^1_0 {x^{2} } \, dx$