The equation that represents the situation will be (0.75x) + 0.8(x + 10) = 101
<h3>How to compute the equation?</h3>
From the information, Jared attempted x shots and made 75% of them. Zach attempted 10 more shots than Jared did and made 80% of them.
Therefore the equation that represents the situation will be:
= (0.75 × x) + 0.8(x + 10) = 101
= 0.75x + 0.8(x + 10) = 101.
Therefore, the equation that represents the situation will be (0.75x) + 0.8(x + 10) = 101
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Answer:
Step-by-step explanation:
Given: In parallelogram DEFG,
DH = x + 1
HF = 3y
GH = 3x - 4
and HE = 5y + 1
Solution: Since, DH,HF, GH and HE represents the diagonals of the parallelogram and we know that the diagonals of the parallelogram bisect each other, therefore
x+1=3y (1)
3x-4=5y+1 (2)
Multiply equation (1) with 3 and then subtract equation (2) from it, we get
3x+3-3x+4=9y-5y-1
7=4y-1
y=2
Substituting the value of y=2 in equation (1), we get
x+1=3(2)
x=5
Therefore, the value of x and y are 5 and 2 respectively.
Answer: 252 i think i tried and i think its right
Step-by-step explanation:
False.
intersects the y-axis => x=0
tan (0+ π/6) = tan π/6 = 0.58
instead of 1.73
Answer:
see explanation
Step-by-step explanation:
To multiply the vector by a scalar, multiply each of the elements by the scalar.
To add 3 vectors add the corresponding elements of each vector
2a + 3b + 4c
= 2![\left[\begin{array}{ccc}2\\3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%5C%5C3%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ 3![\left[\begin{array}{ccc}-4\\1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%5C%5C1%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ 4![\left[\begin{array}{ccc}3\\2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C2%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}4\\6\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%5C%5C6%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}-12\\3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-12%5C%5C3%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}12\\8\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%5C%5C8%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}4-12+12\\6+3+8\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4-12%2B12%5C%5C6%2B3%2B8%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}4\\17\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%5C%5C17%5C%5C%5Cend%7Barray%7D%5Cright%5D)
