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Karolina [17]
3 years ago
15

Rewrite y-3=3(X+1) in standard form

Mathematics
2 answers:
Stels [109]3 years ago
7 0
I believe this is the answer your looking for Y=6+3X

I hope this helps 
viva [34]3 years ago
6 0
The standard from of a line has both variables on one side of the equal sign and a constant on the other side.  (by convention is should be arranged so that the coefficient of x is positive)

y-3=3(x+1)  perform indicated multiplication on right side

y-3=3x+3  subtract 3x from both sides

y-3x-3=3  add 3 to both sides

y-3x=6  multiply both sides by -1

3x-y=-6
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Levi takes his friends on a boat ride.
melomori [17]

Answer:

The distance traveled in Duke Canal is one-fourth the distance traveled on Witham Lake

Step-by-step explanation:good luck

5 0
3 years ago
The length of the base of a right triangle is 32 centimeters, and the height is 10 centimeters. What is the area of the triangle
Bas_tet [7]
10(32)=320, 320/2 Area=160
4 0
2 years ago
Read 2 more answers
Two problems here I need solved! I need every step, so please have that with your answers!!
Free_Kalibri [48]
QUESTION 1

We want to solve,

\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}

We factor the denominator of the fraction on the right hand side to get,

\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.

This implies
\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.

\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}

We multiply through by LCM of
(x-4)(x - 2)

(x - 2) + x(x-4) = 2

We expand to get,

x - 2 + {x}^{2} - 4x= 2

We group like terms and equate everything to zero,

{x}^{2} + x - 4x - 2 - 2 = 0

We split the middle term,

{x}^{2} + - 3x - 4 = 0

We factor to get,

{x}^{2} + x - 4x- 4 = 0

x(x + 1) - 4(x + 1) = 0

(x + 1)(x - 4) = 0

x + 1 = 0 \: or \: x - 4 = 0

x = - 1 \: or \: x = 4

But
x = 4
is not in the domain of the given equation.

It is an extraneous solution.

\therefore \: x = - 1
is the only solution.

QUESTION 2

\sqrt{x+11} -x=-1

We add x to both sides,

\sqrt{x+11} =x-1

We square both sides,

x + 11 = (x - 1)^{2}

We expand to get,

x + 11 = {x}^{2} - 2x + 1

This implies,

{x}^{2} - 3x - 10 = 0

We solve this quadratic equation by factorization,

{x}^{2} - 5x + 2x - 10 = 0

x(x - 5) + 2(x - 5) = 0

(x + 2)(x - 5) = 0

x + 2 = 0 \: or \: x - 5 = 0

x = - 2 \: or \: x = 5

But
x = - 2
is an extraneous solution

\therefore \: x = 5
7 0
3 years ago
Can someone help me please​
sashaice [31]

Answer:

7/10

Step-by-step explanation:

I've attached an image on how you can use the diagram they gave you.

If you color in 7/10s and 7/12s you'll notice that 7/10s is greater.

This is because 1/10 of the whole is greater than 1/12 of the whole.

For 1/10, the whole is being divided into 10, so it equals 0.1.

On the other hand, in 1/12, the whole is being divided by 12, so a part equals 0.083

0.1 is greater than 0.083, so 7 of 0.1 is greater than 7 of 0.083

3 0
2 years ago
Which set of line segments could create a right triangle? (4 points)
kolezko [41]

Answer:

5,13,18

Step-by-step explanation:

guessing

3 0
3 years ago
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