Answer:
The numbers, positive, negative signs and the symbol of elements are used to represent the ions.
Explanation:
Steps to write the ions:
- Write the symbol of an element. For example in case of magnesium we would write Mg.
- In second step write the number of electrons in superscript that are lost or gained by an atom. For example magnesium atom loses two electrons written as followed, Mg².
- In third step write the charge as superscript after the numbers. For example, magnesium loses two electrons that's why we put the positive sign after 2, because by losing the electrons cations are formed. Mg²⁺
- If the atom of an element lose or gain only one electron then 1 is omitted and only the negative or positive sign are written on superscript. For example in case of sodium cation and chlorine anion, Na⁺ , Cl⁻.
Moles * Avogadro constant = 5.52 * <span>6.022 x 10^23</span>
<span> C12H4Cl6 + 23 O2 + 2 H2O → 24 CO2 + 12 HCl </span>
<span>(a) </span>
<span>(13.5 mol O2) x (2 mol H2O / 23 mol O2) = 1.17 mol H2O </span>
<span>(b) </span>
<span>(17.6 mol H2O) x (12 mol HCl / 2 mol H2O) x (36.4611 g HCl/mol) = 3850 g HCl </span>
<span>(c) </span>
<span>(90.4 g HCl) / (36.4611 g HCl/mol) x (24 mol CO2 / 12 mol HCl) = 4.96 mol CO2 </span>
<span>(d) </span>
<span>(106.01 g CO2) / (44.00964 g CO2/mol) x (2 mol C12H4Cl6 / 24 mol CO2) x (360.8782 g C12H4Cl6/mol) = </span>
<span>72.4 g C12H4Cl6 </span>
<span>(e) </span>
<span>(4.2 kg C12H4Cl6) / (360.8782 g C12H4Cl6/mol) x (12 mol HCl / 2 mol C12H4Cl6) x (36.4611 g HCl/mol) = </span>
<span>2.5 kg HCl</span>
<em>D</em> = 1.59 g/mL = 1.59 kg/L
Mass of CCl₄ = 703.55 g – 346.8 g = 357.75 g
<em>D</em> = mass/volume = 357.75 g/225 mL = 1.59 g/mL
(1.59 g/1 mL) × (1 kg/1000 g) × (1000 mL/1 L) = 1.59 kg/L
<span>Scientific notation is the standardized way to
represent any number as the product of a real number and a power of ten. Apply Avogadro's constant which is 6.023x10^23 molecules per mole.
20x10^22 molecules / </span>6.023x10^23 molecules per mole = 0.33 moles.
