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nignag [31]
3 years ago
7

HELP ASAP!!!........

Chemistry
2 answers:
vampirchik [111]3 years ago
4 0
Bleach, Carbon dioxide, Baking soda and table salt
Anna007 [38]3 years ago
4 0
Iron, Carbon Dioxide, Copper, Baking Soda, Oxygen, and Salt.

Looked them up, so not super sure but these are what they gave me!
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Burning one gallon of gasoline releases 20 pounds of CO2 into the air. Harry’s compact car can travel 25 miles on one gallon of
son4ous [18]
There are several information's already given in the question. Based on those information's, the answer can be easily deduced.
Amount of gasoline required by Harry's car to travel 25 miles = 1 gallon
Then
amount of gasoline required
by Harry's car to travel 15000 miles = 15000/25
                                                         = 600 gallons
So 
Amount of CO2 released by burning 1 gallon of gasoline = 20 pounds
Then
Amount of CO2 released
by burning 600 gallon of gasoline = 600 * 20
                                                      = 12000 pounds
From the above deduction, it can be concluded that the amount of CO2 that will be added by Harry's car to the atmosphere is 12000 pounds.
5 0
3 years ago
8. __H2 + __O2-> __H2O
Rus_ich [418]

Anser:

Explanation:

hope this helps

8 0
2 years ago
Please help me ASAP I’ll mark Brainly
mixer [17]

Answer:

cell

chloroplast and cell wall

nucleus

life processes

cell membrane

shape and size

vacuole

Hope it helps

5 0
3 years ago
There is a meme in the image i have what does it mean
Gelneren [198K]

Answer:

The 4s2 is preventing 3d10 from following 1s2 2s2 2p6 3s2 3p6.

Explanation:

the meme is quite common.

5 0
3 years ago
Read 2 more answers
The equilibrium constant for the reaction 2NO2(g) N2O4(g) is Keq = . If a sample at equilibrium was found to contain 0.058 M NO2
Sladkaya [172]

Answer:

\boxed{3.6}

Explanation:

                  2NO₂ ⇌ N₂O₄

E/mol·L⁻¹:   0.058     0.012

K_{\text{eq}} = \dfrac{\text{[N$_{2}$O$_{4}$]}}{\text{[NO$_{2}$]$^{2}$}} = \dfrac{0.012}{0.058^{2}} = \mathbf{3.6} \\\\

\text{The $K_{\text{eq}}$ value would be $\boxed{\mathbf{3.6}}$}

7 0
3 years ago
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